The negative edge triggered JK flip-flop in the Figure has J and K inputs tied to Logic High and a square wave of 10 cycles/second is applied to its clock (C) input.
The frequency of the output Q (in cycles/second) is __.
(rounded off to two decimal places)
The JK flip-flop shown has its J and K inputs connected to Logic High, making it toggle on every negative edge of the clock cycle. Given a clock frequency of 10 cycles/second, we can determine the output frequency, Q, by understanding the toggling behavior.
Step-by-step Solution:
- The JK flip-flop will toggle its output on each negative edge of the clock signal.
- With the clock frequency at 10 Hz, there are 10 negative edges per second.
- Each toggle event occurs on a negative edge, meaning the output frequency Q is half the clock frequency:
Output Frequency (Q) = Clock Frequency / 2 = 10 Hz / 2 = 5 Hz
Thus, the frequency of the output Q is 5.00 cycles/second.
Validation:
The computed frequency of 5.00 cycles/second clearly falls within the provided range of 4.9 to 5.1, confirming its accuracy.
Important Questions from Flip-Flop
What type of Flip Flop is used in Counters?
What is the characteristic of a master-slave flip-flop?
The basic building block of sequential logic circuit is-
A single flip-flop is a modulo __________ counter.
For a JK Flip‐flop
A. When J = 0, K = 1, Q n+1 = 0
B. When J = 1, K = 1, Q n+1 = 1
C. When J = 1, K = 1, Q n+1 =\(\rm \overline{Q_n}\)
D. When J = 1, K = 0, Q n+1 = 1
E. When J = 1, K = 0, Q n+1 = 0
Choose the correct answer from the options given below:
