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Question

The negative edge triggered JK flip-flop in the Figure has J and K inputs tied to Logic High and a square wave of 10 cycles/second is applied to its clock (C) input.
The frequency of the output Q (in cycles/second) is __.
(rounded off to two decimal places)

The JK flip-flop shown has its J and K inputs connected to Logic High, making it toggle on every negative edge of the clock cycle. Given a clock frequency of 10 cycles/second, we can determine the output frequency, Q, by understanding the toggling behavior.

Step-by-step Solution:

  1. The JK flip-flop will toggle its output on each negative edge of the clock signal.
  2. With the clock frequency at 10 Hz, there are 10 negative edges per second.
  3. Each toggle event occurs on a negative edge, meaning the output frequency Q is half the clock frequency:

Output Frequency (Q) = Clock Frequency / 2 = 10 Hz / 2 = 5 Hz

Thus, the frequency of the output Q is 5.00 cycles/second.

Validation:

The computed frequency of 5.00 cycles/second clearly falls within the provided range of 4.9 to 5.1, confirming its accuracy.

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Important Questions from Flip-Flop

  1. Race Around condition can be avoided in Digital logic circuits using _______.

  2. A flip-flop is capable of storing ______ information.

  3. Consider the given circuit.

     In this circuit, the race around

  4. What is the characteristic of a master-slave flip-flop?

  5. Which of the following pair is/are correct?

    I. Astable multivibrator - Flip Flop

    II. Bistable multivibrator - Free running

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