List - I List - II A. $\sin^{2} \omega t$ I. Periodic with time period $T=\frac{\pi}{\omega}$ but not simple harmonic motion (SHM) B. $\sin^{3} (2\omega t)$ II. Periodic with time period $T=\frac{2\pi}{\omega}$ but Not SHM C. $\sin (\omega t) + \cos(\pi \omega t)$ III. Periodic with time period $T=\frac{\pi}{\omega}$ and SHM D. $\cos \omega t + \cos 2\omega t$ IV. Non-periodic
Choose the correct answer from the options given below :
This solution analyzes the periodicity and Simple Harmonic Motion (SHM) properties of the given functions by matching List - I with List - II.
Using the trigonometric identity $\sin^{2} \theta = \frac{1 - \cos(2\theta)}{2}$, we rewrite the function:
$\sin^{2} \omega t = \frac{1}{2} - \frac{1}{2} \cos(2\omega t)$
This expression involves $\cos(2\omega t)$, indicating an angular frequency of $2\omega$. The time period ($T$) is determined by this frequency:
$T = \frac{2\pi}{2\omega} = \frac{\pi}{\omega}$
The function oscillates around a mean value of $1/2$. The deviation from this mean oscillates harmonically with the period $T=\frac{\pi}{\omega}$. This matches the description 'Periodic with time period $T=\frac{\pi}{\omega}$ and SHM' (List - III).
Using the identity $\sin^3\theta = \frac{3\sin\theta - \sin(3\theta)}{4}$, we get:
$\sin^{3} (2\omega t) = \frac{3\sin(2\omega t) - \sin(6\omega t)}{4}$
This function is a sum of two sinusoidal terms with different angular frequencies, $2\omega$ and $6\omega$. The corresponding periods are $T_1 = \frac{2\pi}{2\omega} = \frac{\pi}{\omega}$ and $T_2 = \frac{2\pi}{6\omega} = \frac{\pi}{3\omega}$.
The time period of the combined function is the least common multiple (LCM) of $T_1$ and $T_2$:
$T = \text{LCM}(\frac{\pi}{\omega}, \frac{\pi}{3\omega}) = \frac{\pi}{\omega}$
Since the function is a sum of sinusoids with different frequencies, it is periodic but not SHM. This matches 'Periodic with time period $T=\frac{\pi}{\omega}$ but not SHM' (List - I).
The function is a sum of two sinusoidal terms:
The ratio of their angular frequencies is $\frac{\omega_1}{\omega_2} = \frac{\omega}{\pi \omega} = \frac{1}{\pi}$. Since this ratio is irrational, the sum of these two terms is non-periodic. This matches 'Non-periodic' (List - IV).
The function is a sum of two sinusoidal terms:
The ratio of frequencies is $\frac{\omega_1}{\omega_2} = \frac{1}{2}$, which is rational.
The time period of the sum is the LCM of the individual periods:
$T = \text{LCM}(\frac{2\pi}{\omega}, \frac{\pi}{\omega}) = \frac{2\pi}{\omega}$
As it's a sum of sinusoids with different frequencies, it is periodic but not SHM. This matches 'Periodic with time period $T=\frac{2\pi}{\omega}$ but Not SHM' (List - II).
Based on the analysis:
The correct combination is A-III, B-I, C-IV, D-II.
A simple pendulum has a bob with mass $m$ and charge $q$. The pendulum string has negligible mass. When a uniform and horizontal electric field $\vec{E}$ is applied, the tension in the string changes. The final tension in the string, when pendulum attains an equilibrium position is _________.
(g: acceleration due to gravity)
In an open organ pipe $\nu_3$ and $\nu_6$ are $3^{\text{rd}}$ and $6^{\text{th}}$ harmonic frequencies, respectively. If $\nu_6 - \nu_3 = 2200 \text{ Hz}$ then length of the pipe is _________ mm.
(Take velocity of sound in air is $330 \text{ m/s}$.)
A simple pendulum has a bob with mass $m$ and charge $q$. The pendulum string has negligible mass. When a uniform and horizontal electric field $\vec{E}$ is applied, the tension in the string changes. The final tension in the string, when pendulum attains an equilibrium position is _________.
(g: acceleration due to gravity)
In an open organ pipe $\nu_3$ and $\nu_6$ are $3^{\text{rd}}$ and $6^{\text{th}}$ harmonic frequencies, respectively. If $\nu_6 - \nu_3 = 2200 \text{ Hz}$ then length of the pipe is _________ mm.
(Take velocity of sound in air is $330 \text{ m/s}$.)