First, we evaluate the determinant of the given matrix:
Let \(D = \begin{vmatrix} x & 1 & 1 \\ 1 & y & 1 \\ 1 & 1 & z \end{vmatrix}\). Expanding the determinant, we get: \(D = x(yz - 1 \times 1) - 1(1 \times z - 1 \times 1) + 1(1 \times 1 - y \times 1)\) \(D = x(yz - 1) - (z - 1) + (1 - y)\) \(D = xyz - x - z + 1 + 1 - y\) \(D = xyz - x - y - z + 2\)
We are given that the determinant \(D\) is positive:
\(D > 0\)
Substituting the calculated expression for \(D\):
\(xyz - x - y - z + 2 > 0\)
We are also given the definitions \(p = x + y + z\) and \(q = xyz\). Substitute these into the inequality:
\(q - (x + y + z) + 2 > 0\)
\(q - p + 2 > 0\)
Rearranging the terms to match the options:
\(q + 2 > p\)
This inequality matches Option C.
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?
If $A = \begin{bmatrix} \sin 2\theta & 2 \sin^2 \theta - 1 & 0 \\ \cos 2\theta & 2 \sin \theta \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$, then which of the following statements is/are correct?
1. $A^{-1} = \text{adj}A$
2. $A$ is skew-symmetric matrix
3. $A^{-1} = A^T$
Select the correct answer using the code given below :
If
\(\omega = -\frac{1}{2} + i\frac{\sqrt{3}}{2}\)
then what is
equal to?
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?