Find the LCM of the numbers 780, 2080 and 2600.
31200
Write each number as a product of prime factors.
\(780 = 2^2 \times 3 \times 5 \times 13\).
\(2080 = 2^5 \times 5 \times 13\).
\(2600 = 2^3 \times 5^2 \times 13\).
The LCM takes the highest power of each prime: \(2^5 \times 3 \times 5^2 \times 13\).
\(= 32 \times 3 \times 25 \times 13 = 31200\).
Hence, the LCM is 31200.
The ratio of two numbers is \(3:4\) and their HCF is 7. Their LCM is:
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?