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Question

Find the LCM of the numbers 780, 2080 and 2600.

This question was previously asked in
RRB Group D 2024 Question Paper PDF (21-Dec-2025) (Shift 2)
The correct answer is

31200

Write each number as a product of prime factors.

\(780 = 2^2 \times 3 \times 5 \times 13\).

\(2080 = 2^5 \times 5 \times 13\).

\(2600 = 2^3 \times 5^2 \times 13\).

The LCM takes the highest power of each prime: \(2^5 \times 3 \times 5^2 \times 13\).

\(= 32 \times 3 \times 25 \times 13 = 31200\).

Hence, the LCM is 31200.

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Similar Questions

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Important Questions from LCM and HCF

  1. Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?

  2. A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:

  3. Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

  4. Calculate the HCF of \(\frac{12}{5}\) \(\frac{14}{15}\)  and  \(\frac{16}{17}\) .

  5. Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?

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