It takes 2 hours for Tiwari and Deo to do a job. Tiwari and Hari take 3 hours to do the same job. Deo and Hari take 6 hours to do the same job. Which of the following statements is incorrect?
This problem requires calculating the time each person (Tiwari, Deo, Hari) takes to complete a job individually, based on their combined working times.
Let $T$, $D$, and $H$ represent the time (in hours) taken by Tiwari, Deo, and Hari, respectively, to complete the job alone.
Their corresponding work rates are $1/T$, $1/D$, and $1/H$ (job per hour).
From the problem statement, we can form the following equations based on combined work rates:
Add all three equations:
$ \left(\frac{1}{T} + \frac{1}{D}\right) + \left(\frac{1}{T} + \frac{1}{H}\right) + \left(\frac{1}{D} + \frac{1}{H}\right) = \frac{1}{2} + \frac{1}{3} + \frac{1}{6} $
$ 2\left(\frac{1}{T} + \frac{1}{D} + \frac{1}{H}\right) = \frac{3+2+1}{6} = \frac{6}{6} = 1 $
Therefore, the combined rate of all three is:
$ \frac{1}{T} + \frac{1}{D} + \frac{1}{H} = \frac{1}{2} $ (Equation 4)
Now, find individual rates by subtracting the given equations from Equation 4:
Let's check each option based on our calculated times:
The question asks for the incorrect statement. Based on the calculations, the statement "Hari is the fastest worker" is incorrect.
Aman can do 50% of the job in 16 days, and Bhanu can do 25% of the job in 24 days. In how many days can they do $\frac{1}{4}^{th}$ of the job working together ?