This problem asks us to determine the total time required to fill a fish tank when two taps, each with a different filling rate, are opened simultaneously. We need to find the combined time based on their individual filling times.
First, let's determine the rate at which each tap fills the tank.
When both taps are open, their rates add up. We need to sum the fractions representing their individual rates:
Combined Rate = Rate of Fresh Water Tap + Rate of Salt Water Tap
Combined Rate = $ \frac{1}{40} + \frac{1}{120} $
To add these fractions, we find a common denominator, which is 120:
$ \frac{1}{40} = \frac{1 \times 3}{40 \times 3} = \frac{3}{120} $
Now, add the fractions:
Combined Rate = $ \frac{3}{120} + \frac{1}{120} = \frac{3 + 1}{120} = \frac{4}{120} $
Simplify the combined rate:
Combined Rate = $ \frac{4}{120} = \frac{1}{30} $
This means that when both taps are open, they fill $ \frac{1}{30} $ of the tank every minute.
The time it takes to fill the tank together is the reciprocal of their combined rate. If they fill $ \frac{1}{30} $ of the tank per minute, the total time to fill 1 whole tank is:
Total Time = $ \frac{1}{\text{Combined Rate}} $
Total Time = $ \frac{1}{1/30} $
Total Time = 30 minutes
If both the fresh water tap and the salt water tap are open simultaneously, it will take 30 minutes to fill the fish tank.
Aman can do 50% of the job in 16 days, and Bhanu can do 25% of the job in 24 days. In how many days can they do $\frac{1}{4}^{th}$ of the job working together ?