A and B complete a work in 6 days. If A alone can do it in 9 days, then B alone can do $\frac{1}{3}$ of the same work in ________ (days).
This problem involves calculating the time taken by an individual (B) to complete a portion of a task, given information about the combined time taken by two people (A and B) and the time taken by one of them (A) individually.
We need to determine how much work A and B do per day, both together and individually.
To find B's work rate, we subtract A's rate from the combined rate:
B's work rate = (Combined work rate of A and B) - (A's work rate)
B's work rate = $\frac{1}{6} - \frac{1}{9}$
To subtract these fractions, we find a common denominator, which is 18:
B's work rate = $\frac{3}{18} - \frac{2}{18} = \frac{1}{18}$ of the work per day.
Since B completes $\frac{1}{18}$ of the work each day, the total time B would take to complete the entire work (1 unit) is the reciprocal of B's work rate:
Time for B (full work) = $\frac{1}{\text{B's work rate}} = \frac{1}{1/18} = 18$ days.
The question asks for the time B takes to complete $\frac{1}{3}$ of the same work. We can calculate this by multiplying the time needed for the full work by $\frac{1}{3}$:
Time for B ($\frac{1}{3}$ work) = (Time for B (full work)) $\times \frac{1}{3}$
Time for B ($\frac{1}{3}$ work) = $18 \times \frac{1}{3}$
Time for B ($\frac{1}{3}$ work) = $\frac{18}{3} = 6$ days.
Therefore, B alone can do $\frac{1}{3}$ of the same work in 6 days.
Aman can do 50% of the job in 16 days, and Bhanu can do 25% of the job in 24 days. In how many days can they do $\frac{1}{4}^{th}$ of the job working together ?
Ravina, Sujata, and Saroj can complete a work of painting separately in 32, 48, and 64 hours, respectively. They started working together, but Saroj left after 5 hours. From the 6th hour, Ravina and Sujata decided to work on alternate hours starting with Ravina. In how much time will the entire work of painting be completed?