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Question

In the given figure, the vectors u and v are related as: Au = v by a transformation matrix A.
 

The correct choice of matrix A is

The correct answer is

\(  \begin{bmatrix} \frac{4}{5}  &   \frac{3}{5} \\-\frac{3}{5} &   \frac{4}{5}  \end{bmatrix}\)

To find the correct transformation matrix \( A \) that relates vectors \( \mathbf{u} \) and \( \mathbf{v} \), we need to express vector \( \mathbf{v} \) as a transformation of vector \( \mathbf{u} \) using the matrix \( A \). The relationship is given as:

\( A \mathbf{u} = \mathbf{v} \).

From the diagram:

  • \( \mathbf{u} = \begin{bmatrix} 4 \\ 3 \end{bmatrix} \)
  • \( \mathbf{v} = \begin{bmatrix} 5 \\ 0 \end{bmatrix} \)

We need to find \( A \) such that:

\[ \begin{bmatrix} a & b \\ c & d \end{bmatrix} \begin{bmatrix} 4 \\ 3 \end{bmatrix} = \begin{bmatrix} 5 \\ 0 \end{bmatrix} \]

This yields the following equations:

  1. \( 4a + 3b = 5 \)
  2. \( 4c + 3d = 0 \)

These are two linear equations in terms of the elements of matrix \( A \).

Solving these equations gives:

\[ \text{From Equation 1:} \quad a = \frac{4}{5}, \quad b = \frac{3}{5}. \] \[ \text{From Equation 2:} \quad c = -\frac{3}{5}, \quad d = \frac{4}{5}. \]

Thus, the matrix \( A \) is:

\( \begin{bmatrix} \frac{4}{5} & \frac{3}{5} \\ -\frac{3}{5} & \frac{4}{5} \end{bmatrix} \)

Checking the options given, this corresponds to the first option provided in the question.

Therefore, the correct choice of matrix \( A \) is:

\( \begin{bmatrix} \frac{4}{5} & \frac{3}{5} \\ -\frac{3}{5} & \frac{4}{5} \end{bmatrix} \)
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Important Questions from Algebra (Notes)

  1. If $(y-12) = 4\sqrt{5}$, then find the value of $\sqrt{y-3} - \frac{1}{\sqrt{y-3}}$.
  2. If $x^2 + \frac{1}{x^2} = 16$ and $x \neq 0$, then what is the value of $x^4 + \frac{1}{x^4}$?
  3. In the expansion of (x + 9)(x - 6)(x + 5), what is the coefficient of x?
  4. The roots of the equation $ax^3-24x^2+188x-480=0$ are three consecutive even natural numbers. The value of a is _____.
  5. A square matrix having all the elements above the leading diagonal equal to zero is known as:
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