In the given figure, PQRS is a parallelogram with PS = 7 cm, PT = 4 cm and PV = 5 cm. What is the length of RS in cm? (The diagram is representative.)
To solve this question, we need to determine the length of RS in the parallelogram PQRS. Given are PS = 7 cm, PT = 4 cm, and PV = 5 cm.
First, observe that the given figure contains right triangles \(PTQ\) and \(PVR\):
Since PQRS is a parallelogram, opposite sides are equal, hence PQ = RS.
Using the Pythagorean theorem in the right triangle \(\triangle PVR\), we have:
\(PV^2 + VR^2 = PR^2\)
We know: \(PV = 5\) cm.
To find VR, observe that VR = QT:
\(QT = \frac{PS \times PT}{PV} = \frac{7 \times 4}{5} = \frac{28}{5} \text{ cm}\)
Since opposite sides in a parallelogram are equal:
\(RS = QT = \frac{28}{5} \text{ cm}\)
Thus, the length of RS is \(\frac{28}{5} \text{ cm}\), which matches the correct option.
| Option | Length |
|---|---|
| \(\frac{20}{7}\) | Doesn't satisfy |
| \(\frac{28}{5}\) | Correct, as computed |
| \(\frac{9}{2}\) | Doesn't satisfy |
| \(\frac{35}{4}\) | Doesn't satisfy |
Therefore, the correct answer is \(\frac{28}{5}\).
In the given figure, $P, Q$, and $R$ are three points on a circle of radius 10 cm with $O$ as its center, $\overline{PQ} = \overline{RQ}$, and $\angle PQR = 45^\circ$. The figure is representative.
The area of the shaded region $PQRO$ is ______________ cm$^2$.
