214614637147612414616212
The question asks us to find the number of times the digits 4, 1, and 6 appear consecutively in a specific order within the given sequence. The required pattern is that the digit 1 must be in the middle, with 4 and 6 on either side. This means we are looking for the specific combinations 416 or 614.
The given sequence of digits is:
$214614637147612414616212$
We need to scan this sequence to find occurrences of either "416" or "614". Let's examine the sequence step-by-step:
By carefully scanning the sequence, we identified only one occurrence of the required pattern (614).
Therefore, the numbers 4, 1, and 6 appeared together with 1 in the middle and 4 and 6 on either side exactly one time.
Six friends A, B, C, D, E and F are sitting in two lines, facing the north. Three persons are sitting in each line. F is sitting in the middle. C is just behind B. D is to the immediate right of E. B is to the immediate left of F. Which three persons are sitting in the same line?
In the series 5442673314884743581, the number of 4s that are completely divisible by the number on their right but not divisible by the number on their left is:
Refer to the following series and answer the question (all numbers are single digit numbers only).
(Left) 1 2 6 5 6 8 1 5 8 6 9 8 3 3 5 8 9 4 7 8 (Right)
How many such even digits are there, each of which is immediately preceded by an odd digit and also immediately followed by an odd digit?
Each of the digits in the number 9362145 is arranged in ascending order from left to right. What will be the sum of the digits which are second from the left and third from the right in the number thus formed?
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 3842675, how many digits will appear more than once in the new number thus formed?