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Question

If 1 is added to each even digit and 1 is subtracted from each odd digit in the number 937612548, then what will be the sum of all the odd digits in the new number thus formed?

This question was previously asked in
RRB NTPC 2024 CBT 1 Question Paper (28-Aug-2025) (Shift 3)
The correct answer is
24

The problem asks us to transform a given number by altering its digits based on whether they are even or odd, and then find the sum of the odd digits in the resulting number.

Digit Transformation Process

The original number is 937612548.

The rules for transformation are:

  • Add 1 to each even digit.
  • Subtract 1 from each odd digit.

Applying Transformation Rules

Let's apply these rules to each digit of 937612548:

  • 9 (odd) becomes $9 - 1 = 8$
  • 3 (odd) becomes $3 - 1 = 2$
  • 7 (odd) becomes $7 - 1 = 6$
  • 6 (even) becomes $6 + 1 = 7$
  • 1 (odd) becomes $1 - 1 = 0$
  • 2 (even) becomes $2 + 1 = 3$
  • 5 (odd) becomes $5 - 1 = 4$
  • 4 (even) becomes $4 + 1 = 5$
  • 8 (even) becomes $8 + 1 = 9$

The new number formed by these transformed digits is 826703459.

Summing New Odd Digits

Now, we need to identify the odd digits in the new number (826703459) and calculate their sum.

The digits in the new number are: 8, 2, 6, 7, 0, 3, 4, 5, 9.

The odd digits in this new sequence are: 7, 3, 5, 9.

The sum of these odd digits is:

$ 7 + 3 + 5 + 9 = 24 $

Therefore, the sum of all the odd digits in the new number formed is 24.

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Important Questions from Number Arrangement

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