This solution identifies how many digits in the number 9254631 remain in their original places after sorting the digits in ascending order.
The original number is 9254631. The digits and their original positions are:
The digits present in the number 9254631 are {9, 2, 5, 4, 6, 3, 1}.
Arranging these digits in ascending order results in: 1, 2, 3, 4, 5, 6, 9.
The new number formed by this arrangement is 1234569.
Below is a comparison of the digits in their original positions versus their positions after sorting:
| Original Position | Original Digit | Sorted Digit |
|---|---|---|
| 1 | 9 | 1 |
| 2 | 2 | 2 |
| 3 | 5 | 3 |
| 4 | 4 | 4 |
| 5 | 6 | 5 |
| 6 | 3 | 6 |
| 7 | 1 | 9 |
We count the number of positions where the digit in the original number is the same as the digit in the sorted number at that specific position.
Therefore, there are Two digits ('2' and '4') whose positions remain unchanged.
Six friends A, B, C, D, E and F are sitting in two lines, facing the north. Three persons are sitting in each line. F is sitting in the middle. C is just behind B. D is to the immediate right of E. B is to the immediate left of F. Which three persons are sitting in the same line?
In the series 5442673314884743581, the number of 4s that are completely divisible by the number on their right but not divisible by the number on their left is:
Refer to the following series and answer the question (all numbers are single digit numbers only).
(Left) 1 2 6 5 6 8 1 5 8 6 9 8 3 3 5 8 9 4 7 8 (Right)
How many such even digits are there, each of which is immediately preceded by an odd digit and also immediately followed by an odd digit?
Each of the digits in the number 9362145 is arranged in ascending order from left to right. What will be the sum of the digits which are second from the left and third from the right in the number thus formed?
If 1 is added to each odd digit and 2 is subtracted from each even digit in the number 3842675, how many digits will appear more than once in the new number thus formed?