In series–parallel combination of resistance, the minimum number of resistance required is _____.
three
A series-parallel combination of resistances is a circuit that contains components connected both in series and in parallel. To have a true series-parallel combination, you need at least one section connected in series and another section connected in parallel within the same circuit arrangement.
Let's consider the minimum number of resistors needed to create a circuit that exhibits both series and parallel characteristics:
Consider three resistors, R1, R2, and R3. We can create a series-parallel combination as follows:
$$ R_{p} = \frac{R_{2} \times R_{3}}{R_{2} + R_{3}} $$
$$ R_{total} = R_{1} + R_{p} = R_{1} + \frac{R_{2} \times R_{3}}{R_{2} + R_{3}} $$
This arrangement clearly shows both a series connection (R1 is in series with the parallel group) and a parallel connection (R2 and R3 are in parallel). Therefore, a minimum of three resistors is required to form a series-parallel combination.
Three resisters of 3 ohm, 10 ohm and 15 ohm are connected in parallel in a 30 V circuit. The current will that flow through the 3-ohm resistor is:
If n identical resistance, each of resistance R, are connected in parallel, the equivalent resistance is:
Four 100 Ω resistors are connected in parallel. The equivalent resistance of the parallel connection is:
Consider the below statements with respect to the series circuit and Identify the correct answer.
Statement A: The same current flows through each resistor in series.
Statement B: In a series circuit, the voltage drops across each resistor will be directly proportional to the capacity of the resistor.