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Question

In pea plants, purple color of flowers is determined by the dominant allele while white color is determined by the recessive allele. A genetic cross between two purple flower-bearing plants results in an offspring with white flowers. The probability that the third offspring from these parents will have purple flowers is ________ (rounded off to 2 decimal places).

Genetic Analysis of Pea Flower Color

To determine the probability of the third offspring having purple flowers, we must first identify the genotypes of the parent plants based on the given phenotypes and the resulting offspring.

1. Identification of Alleles and Genotypes

  • Let \( P \) represent the dominant allele for purple flowers.
  • Let \( p \) represent the recessive allele for white flowers.
  • Since both parents have purple flowers but produced an offspring with white flowers (\( pp \)), each parent must carry one recessive allele.
  • Therefore, both parents are heterozygous: \( Pp \times Pp \).

2. Determining the Probabilities

Using a Punnett square for the cross \( Pp \times Pp \), we can determine the expected genotypic and phenotypic ratios of the offspring:

𝑃 𝑝 𝑃 𝑃 𝑃 𝑃 𝑝 𝑝 𝑃 𝑝 𝑝 𝑝 P p ​ P PP Pp ​ p Pp pp ​ ​

The resulting phenotypes are:

  • Purple flowers: \( PP \) or \( Pp \) (3 out of 4)
  • White flowers: \( pp \) (1 out of 4)

The probability of an offspring having purple flowers is:

$$ P(\text{Purple}) = \frac{3}{4} = 0.75 $$

3. Calculation for the Third Offspring

In Mendelian genetics, each fertilization event is an independent event. The phenotype of previous offspring (such as the first offspring being white) does not influence the probability of the phenotype for subsequent offspring.

Thus, the probability that the third offspring will have purple flowers remains the same as any other individual offspring from this cross.

Probability: \( 0.75 \)

Final Answer:

The probability that the third offspring from these parents will have purple flowers is 0.75.

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Important Questions from Mendelian Inheritance

  1. Mendel's 'law of segregation' applies to the segregation of __________ during gamete formation.
  2. Fabry disease in humans is a X-linked disease. The probability (in percentage) for a phenotypically normal father and a carrier mother to have a son with Fabry disease is ________.
  3. The allele associated with albinism in humans is recessive ($c$). The probability that an albino male ($cc$) and a carrier female ($Cc$) will have an offspring with normal skin pigmentation is _________. 

    (Round off to one decimal place)

  4. The blood group of the mother is A⁺ and that of the father is AB⁺. Which of the following statements is/are correct?
  5. Assuming independent assortment and no recombination, the number of different combinations of maternal and paternal chromosomes in gametes of an organism with a diploid number of 12 is ________.
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