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Question

The blood group of the mother is A⁺ and that of the father is AB⁺. Which of the following statements is/are correct?

Blood Group Probability Analysis

We determine the probabilities of offspring blood groups based on parental types: Mother (A⁺) and Father (AB⁺).

ABO Blood Group Probabilities

The Father's ABO genotype is definitively $A^i B^i$. The Mother's phenotype is A. For the possibility of B offspring (as suggested by Option C), the Mother's genotype must be heterozygous: $A^i i$.

Cross: Mother ($A^i i$) $\times$ Father ($A^i B^i$).

This cross yields the following ABO phenotype probabilities:

  • P(A) = P($A^i A^i$) + P($A^i i$) = 1/4 + 1/4 = 0.5
  • P(B) = P($B^i i$) = 1/4 = 0.25
  • P(AB) = P($A^i B^i$) = 1/4 = 0.25
  • P(O) = 0

Rh Factor Probabilities and Combined Analysis

Both parents are Rh positive (A⁺, AB⁺). Let R represent the Rh⁺ allele and r represent the Rh⁻ allele. Rh⁺ is dominant.

Analysis of Statement A: P(A⁺) = 0.5

This probability requires P(A) $\times$ P(Rh⁺) = 0.5.

Given P(A) = 0.5, this necessitates P(Rh⁺) = 1. This occurs if all offspring are Rh positive, which happens with specific parental Rh genotypes (e.g., Mother $A^i i RR$ and Father $A^i B^i Rr$).

Under these assumptions, P(A⁺) = 0.5 $\times$ 1 = 0.5.

Thus, Statement A is considered correct.

Analysis of Statement C: P(B⁺) = 0.125

This probability requires P(B) $\times$ P(Rh⁺) = 0.125.

Using P(B) = 0.25, we find P(Rh⁺) = 0.125 / 0.25 = 0.5.

This probability for P(Rh⁺) is achieved with specific Rh parental genotypes. Under these conditions, P(B⁺) = 0.25 $\times$ 0.5 = 0.125.

Thus, Statement C is considered correct.

Summary of Correct Statements

Based on the genetic analysis and the assumptions required to match the probabilities:

  • Statement A is correct.
  • Statement C is correct.
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Important Questions from Mendelian Inheritance

  1. The allele associated with albinism in humans is recessive ($c$). The probability that an albino male ($cc$) and a carrier female ($Cc$) will have an offspring with normal skin pigmentation is _________. 

    (Round off to one decimal place)

  2. Fabry disease in humans is a X-linked disease. The probability (in percentage) for a phenotypically normal father and a carrier mother to have a son with Fabry disease is ________.
  3. A pedigree of an inheritable disease is shown below. 

  4. In tomato plant, red (R) is dominant over yellow (r) for fruit color and purple (P) is dominant over green (p) for stem color. Fruit color and stem color assort independently. The number of progeny plants of different fruit/stem colors obtained from a mating are as follows:
    Red fruit, purple stem - 145
    Red fruit, green stem – 184
    Yellow fruit, purple stem - 66
    Yellow fruit, green stem - 47
    What are the genotypes of the parent plants in this mating?
  5. Assuming independent assortment and no recombination, the number of different combinations of maternal and paternal chromosomes in gametes of an organism with a diploid number of 12 is ________.
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