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Question

In tomato plant, red (R) is dominant over yellow (r) for fruit color and purple (P) is dominant over green (p) for stem color. Fruit color and stem color assort independently. The number of progeny plants of different fruit/stem colors obtained from a mating are as follows:
Red fruit, purple stem - 145
Red fruit, green stem – 184
Yellow fruit, purple stem - 66
Yellow fruit, green stem - 47
What are the genotypes of the parent plants in this mating?

The correct answer is
RrPp x Rrpp

Dihybrid Cross Analysis: Parent Genotype Determination

Phenotypic Ratio Calculation

First, calculate the observed phenotypic ratios for each trait separately from the progeny data:

  • Fruit Color:
    • Red Phenotype Count: 145 + 184 = 329
    • Yellow Phenotype Count: 66 + 47 = 113
    • Observed Ratio (Red:Yellow) = 329 : 113. This simplifies to approximately 3:1.
  • Stem Color:
    • Purple Phenotype Count: 145 + 66 = 211
    • Green Phenotype Count: 184 + 47 = 231
    • Observed Ratio (Purple:Green) = 211 : 231. This simplifies to approximately 1:1.

Deducing Parental Genotypes

Interpret these ratios to determine the likely genotypes of the parent plants:

  • A 3:1 phenotypic ratio typically results from a monohybrid cross between two heterozygotes. For fruit color, this implies the parents had genotypes Rr x Rr.
  • A 1:1 phenotypic ratio typically results from a cross between a heterozygote and a homozygous recessive parent. For stem color, this implies the genotypes were Pp x pp.

Synthesizing Parent Genotypes

Given that the genes assort independently, combine the deduced genotypes for each parent:

  • Parent 1: Must be heterozygous for fruit color (Rr) and heterozygous for stem color (Pp). Its genotype is RrPp.
  • Parent 2: Must be heterozygous for fruit color (Rr) and homozygous recessive for stem color (pp). Its genotype is Rrpp.

Therefore, the parental genotypes are RrPp x Rrpp.

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Important Questions from Mendelian Inheritance

  1. Mendel's 'law of segregation' applies to the segregation of __________ during gamete formation.
  2. Fabry disease in humans is a X-linked disease. The probability (in percentage) for a phenotypically normal father and a carrier mother to have a son with Fabry disease is ________.
  3. The allele associated with albinism in humans is recessive ($c$). The probability that an albino male ($cc$) and a carrier female ($Cc$) will have an offspring with normal skin pigmentation is _________. 

    (Round off to one decimal place)

  4. The blood group of the mother is A⁺ and that of the father is AB⁺. Which of the following statements is/are correct?
  5. Assuming independent assortment and no recombination, the number of different combinations of maternal and paternal chromosomes in gametes of an organism with a diploid number of 12 is ________.
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