We need to calculate the conditional probability that a student guessed the answer, given they got it right. This involves understanding conditional probability and applying Bayes' Theorem.
The question asks for the probability that the student was guessing given that they answered correctly. This is represented as \(P(G | C)\).
Bayes' Theorem provides the formula:
\(P(G | C) = \frac{P(C | G) \times P(G)}{P(C)}\)
To use Bayes' Theorem, we first need to find the total probability of answering correctly, \(P(C)\). We can calculate this using the law of total probability, considering both cases: knowing the answer and guessing.
\(P(C) = P(C | K) \times P(K) + P(C | G) \times P(G)\)
Substitute the known values:
\(P(C) = (1 \times 0.90) + (\frac{1}{4} \times 0.10)\)
\(P(C) = 0.90 + 0.025\)
\(P(C) = 0.925\)
Now, substitute the calculated \(P(C)\) and the given probabilities into Bayes' Theorem to find \(P(G | C)\):
\(P(G | C) = \frac{P(C | G) \times P(G)}{P(C)}\)
\(P(G | C) = \frac{0.025}{0.925}\)
To simplify this fraction, we can convert the decimals to fractions:
\(0.025 = \frac{25}{1000} = \frac{1}{40}\)
\(0.925 = \frac{925}{1000} = \frac{37}{40}\)
Now perform the division:
\(P(G | C) = \frac{1/40}{37/40}\)
\(P(G | C) = \frac{1}{40} \times \frac{40}{37}\)
\(P(G | C) = \frac{1}{37}\)
The probability that the student was guessing, given they answered correctly, is 1/37.
A certain disease is difficult to be diagnosed and the probability of correctly diagnosing the disease is 0.6. If any patient, after the correct diagnosis, has 40% chances of dying. However, an incorrect diagnosis enhances the probability of death to 0.7. If a patient has died after the treatment, what is the probability that the disease was diagnosed correctly?