This solution explains how to find the area of a triangle when two sides and the angle between them are given. We are given a triangle ABC with specific measurements for two sides and the angle between them.
The area of a triangle can be calculated using the formula when two sides and the angle between them are known:
Area = \(\frac{1}{2} \times \text{side}_1 \times \text{side}_2 \times \sin(\text{included angle})\)
In this specific triangle ABC, the sides are AB and AC, and the angle between them is \(\angle A\). So the formula becomes:
Area of \(\triangle ABC = \frac{1}{2} \times AB \times AC \times \sin(\angle A)\)
Substitute the known values into the area formula:
Area = \(\frac{1}{2} \times AB \times AC \times \sin(\angle A)\)
Area = \(\frac{1}{2} \times 7 \, \text{cm} \times 12 \, \text{cm} \times \sin(30^\circ)\)
We know the value of \(\sin(30^\circ)\) is \(\frac{1}{2}\). Substitute this value into the equation:
Area = \(\frac{1}{2} \times 7 \times 12 \times \frac{1}{2}\)
Now, perform the multiplication:
Area = \(\frac{7 \times 12 \times 1}{2 \times 2}\)
Area = \(\frac{84}{4}\)
Area = \(21\)
The unit for the area is square centimeters (cm\(^2\)).
Area = \(21 \, \text{cm}^2\)
The area of the triangle ABC is \(21 \, \text{cm}^2\).
What is \(AB + BC\) equal to?
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Which of the statements given above is/are correct?
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