This problem involves calculating the time taken to complete a task (building a wall) where work is done by a builder and simultaneously undone by a destroyer.
For the first 15 hours, both the builder and the destroyer work together. To find the net rate of work during this period, we subtract the destroyer's rate from the builder's rate:
This means that while both were working, the effective progress towards building the wall was $ \frac{1}{20} $ of the wall per hour.
Now, let's calculate the amount of the wall built in the first 15 hours:
After 15 hours, the destroyer stops working. The remaining portion of the wall needs to be built solely by the builder.
The builder continues working alone to complete this remaining $ \frac{1}{4} $ of the wall. We use the builder's individual rate to find the time needed:
The total time taken to build the wall is the sum of the time they worked together and the time the builder worked alone.
Therefore, the total time taken to build the wall was 17.5 hours.
Aman can do 50% of the job in 16 days, and Bhanu can do 25% of the job in 24 days. In how many days can they do $\frac{1}{4}^{th}$ of the job working together ?
Ravina, Sujata, and Saroj can complete a work of painting separately in 32, 48, and 64 hours, respectively. They started working together, but Saroj left after 5 hours. From the 6th hour, Ravina and Sujata decided to work on alternate hours starting with Ravina. In how much time will the entire work of painting be completed?