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Question

In a computer game, a builder can build a wall in 10 hours while a destroyer can completely demolish such a wall in 20 hours. In the beginning, both builder and destroyer were set to work together on a basic level. But after 15 hours the destroyer was withdrawn. What was the total time (in hours) taken to build the wall?

The correct answer is
17.5

Analyzing the Builder and Destroyer Rates

This problem involves calculating the time taken to complete a task (building a wall) where work is done by a builder and simultaneously undone by a destroyer.

  • The builder's rate of work is the amount of wall they can build per hour. Since the builder builds one wall in 10 hours, their rate is: $ \frac{1}{10} \text{ wall/hour} $
  • The destroyer's rate of work is the amount of wall they can demolish per hour. Since the destroyer demolishes one wall in 20 hours, their rate is: $ \frac{1}{20} \text{ wall/hour} $ This is considered negative work concerning the building process.

Calculating Work Done Together

For the first 15 hours, both the builder and the destroyer work together. To find the net rate of work during this period, we subtract the destroyer's rate from the builder's rate:

  • Combined Rate = Builder's Rate - Destroyer's Rate
  • Combined Rate = $ \frac{1}{10} - \frac{1}{20} $
  • To subtract these fractions, we find a common denominator, which is 20:
  • Combined Rate = $ \frac{2}{20} - \frac{1}{20} = \frac{1}{20} \text{ wall/hour} $

This means that while both were working, the effective progress towards building the wall was $ \frac{1}{20} $ of the wall per hour.

Now, let's calculate the amount of the wall built in the first 15 hours:

  • Work Done = Combined Rate × Time
  • Work Done = $ \frac{1}{20} \text{ wall/hour} \times 15 \text{ hours} $
  • Work Done = $ \frac{15}{20} = \frac{3}{4} $ of the wall.

Calculating Remaining Work and Time

After 15 hours, the destroyer stops working. The remaining portion of the wall needs to be built solely by the builder.

  • Remaining Work = Total Wall - Work Done
  • Remaining Work = $ 1 - \frac{3}{4} = \frac{1}{4} $ of the wall.

The builder continues working alone to complete this remaining $ \frac{1}{4} $ of the wall. We use the builder's individual rate to find the time needed:

  • Time = Work / Rate
  • Time for Builder Alone = Remaining Work / Builder's Rate
  • Time for Builder Alone = $ \frac{1/4}{1/10} $ hours
  • Time for Builder Alone = $ \frac{1}{4} \times \frac{10}{1} = \frac{10}{4} = 2.5 $ hours.

Determining Total Time Taken

The total time taken to build the wall is the sum of the time they worked together and the time the builder worked alone.

  • Total Time = Time Worked Together + Time Builder Worked Alone
  • Total Time = 15 hours + 2.5 hours
  • Total Time = 17.5 hours.

Therefore, the total time taken to build the wall was 17.5 hours.

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Important Questions from Time & Work (Notes)

  1. A fresh water tap fills a fish tank in 40 minutes. The same tank is filled by a salt water tap in 120 minutes. If both the taps are open, how many minutes will it take to fill the tank?
  2. A completes $\frac{7}{10}$ of a work in 15 days and then he completes the remaining work with the help of B in 5 days. In how many days can A and B together complete the entire work?
  3. Aman can do 50% of the job in 16 days, and Bhanu can do 25% of the job in 24 days. In how many days can they do $\frac{1}{4}^{th}$  of the job working together ?

  4. X can finish a job in $141$ days. He worked for $57$ days alone and the remaining work was completed by Y, in $84$ days. How many days would both together take to complete the entire job?
  5. Ravina, Sujata, and Saroj can complete a work of painting separately in 32, 48, and 64 hours, respectively. They started working together, but Saroj left after 5 hours. From the 6th hour, Ravina and Sujata decided to work on alternate hours starting with Ravina. In how much time will the entire work of painting be completed?

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