In a college, if 15% of the boys are the same in number as one-third of the girls, then find the ratio of the number of boys to that of girls in the college.
20 : 9
Let's break down this college ratio problem step-by-step. We are given a relationship between the number of boys and the number of girls in a college and asked to find the ratio of boys to girls.
Let:
According to the question, 15% of the boys are equal in number to one-third of the girls. We can write this relationship as an equation.
First, let's express the given percentages and fractions mathematically:
Now, we can set up the equation based on the problem statement:
$\frac{3}{20} \times B = \frac{1}{3} \times G$
We need to find the ratio of the number of boys to that of girls, which is $B : G$ or $\frac{B}{G}$. To find this ratio from our equation, we need to isolate the term $\frac{B}{G}$.
Let's rearrange the equation:
Start with: $\frac{3}{20} B = \frac{1}{3} G$
To get $\frac{B}{G}$ on one side, we can divide both sides of the equation by $G$ (assuming $G \neq 0$):
$\frac{\frac{3}{20} B}{G} = \frac{\frac{1}{3} G}{G}$
$\frac{3}{20} \times \frac{B}{G} = \frac{1}{3}$
Now, to isolate $\frac{B}{G}$, we need to multiply both sides of the equation by the reciprocal of $\frac{3}{20}$, which is $\frac{20}{3}$:
$\left(\frac{20}{3}\right) \times \left(\frac{3}{20} \times \frac{B}{G}\right) = \left(\frac{20}{3}\right) \times \left(\frac{1}{3}\right)$
On the left side, $\frac{20}{3}$ and $\frac{3}{20}$ cancel out, leaving $\frac{B}{G}$.
On the right side, we multiply the numerators and the denominators:
$\frac{B}{G} = \frac{20 \times 1}{3 \times 3}$
$\frac{B}{G} = \frac{20}{9}$
This means the ratio of the number of boys to the number of girls is $20:9$.
Let's verify with an example. If $B = 200$ and $G = 90$, then the ratio is $200:90 = 20:9$.
Since $30 = 30$, the condition in the question is met, confirming our ratio $20:9$ is correct.
The ratio of the number of boys to that of girls is $20 : 9$. Looking at the options provided, this matches one of them.
| Concept | Explanation | How it Applied Here |
|---|---|---|
| Ratio | A comparison of two quantities. Expressed as $a:b$ or $\frac{a}{b}$. | We needed to find the ratio $B:G$. |
| Percentage | A fraction out of 100. $x\% = \frac{x}{100}$. | Converted 15% to $\frac{15}{100}$ or $\frac{3}{20}$. |
| Fraction | Represents a part of a whole or a division. | Used $\frac{1}{3}$ for one-third of girls. |
| Algebraic Equation | A statement that two mathematical expressions are equal. | Set up the equation $\frac{3}{20} B = \frac{1}{3} G$. |
| Solving Equations | Using inverse operations to find the value of a variable or expression. | Rearranged the equation to solve for $\frac{B}{G}$. |
Understanding how percentages, fractions, and ratios relate to each other is crucial for solving many math problems.
Being comfortable converting between these forms helps in setting up and solving such problems efficiently.
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