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Question

In a college, if 15% of the boys are the same in number as one-third of the girls, then find the ratio of the number of boys to that of girls in the college.

The correct answer is

20 : 9

Finding the Ratio of Boys to Girls in College

Let's break down this college ratio problem step-by-step. We are given a relationship between the number of boys and the number of girls in a college and asked to find the ratio of boys to girls.

Let:

  • $B$ represent the number of boys in the college.
  • $G$ represent the number of girls in the college.

According to the question, 15% of the boys are equal in number to one-third of the girls. We can write this relationship as an equation.

First, let's express the given percentages and fractions mathematically:

  • 15% of boys can be written as $\frac{15}{100} \times B$. This simplifies to $\frac{3}{20} \times B$.
  • One-third of girls can be written as $\frac{1}{3} \times G$.

Now, we can set up the equation based on the problem statement:

$\frac{3}{20} \times B = \frac{1}{3} \times G$

We need to find the ratio of the number of boys to that of girls, which is $B : G$ or $\frac{B}{G}$. To find this ratio from our equation, we need to isolate the term $\frac{B}{G}$.

Let's rearrange the equation:

Start with: $\frac{3}{20} B = \frac{1}{3} G$

To get $\frac{B}{G}$ on one side, we can divide both sides of the equation by $G$ (assuming $G \neq 0$):

$\frac{\frac{3}{20} B}{G} = \frac{\frac{1}{3} G}{G}$

$\frac{3}{20} \times \frac{B}{G} = \frac{1}{3}$

Now, to isolate $\frac{B}{G}$, we need to multiply both sides of the equation by the reciprocal of $\frac{3}{20}$, which is $\frac{20}{3}$:

$\left(\frac{20}{3}\right) \times \left(\frac{3}{20} \times \frac{B}{G}\right) = \left(\frac{20}{3}\right) \times \left(\frac{1}{3}\right)$

On the left side, $\frac{20}{3}$ and $\frac{3}{20}$ cancel out, leaving $\frac{B}{G}$.

On the right side, we multiply the numerators and the denominators:

$\frac{B}{G} = \frac{20 \times 1}{3 \times 3}$

$\frac{B}{G} = \frac{20}{9}$

This means the ratio of the number of boys to the number of girls is $20:9$.

Let's verify with an example. If $B = 200$ and $G = 90$, then the ratio is $200:90 = 20:9$.

  • 15% of boys = $0.15 \times 200 = 30$.
  • One-third of girls = $\frac{1}{3} \times 90 = 30$.

Since $30 = 30$, the condition in the question is met, confirming our ratio $20:9$ is correct.

Summary of Ratio Calculation Steps

  1. Define variables for the quantities (Boys $B$, Girls $G$).
  2. Translate the word problem into an algebraic equation: $15\% \text{ of } B = \frac{1}{3} \text{ of } G$.
  3. Convert percentage to a fraction or decimal: $0.15 B = \frac{1}{3} G$ or $\frac{3}{20} B = \frac{1}{3} G$.
  4. Rearrange the equation to find the ratio $\frac{B}{G}$.
  5. Simplify the resulting fraction to get the final ratio.

Final Ratio Result

The ratio of the number of boys to that of girls is $20 : 9$. Looking at the options provided, this matches one of them.

Revision Table: Key Concepts for Ratio Problems

Concept Explanation How it Applied Here
Ratio A comparison of two quantities. Expressed as $a:b$ or $\frac{a}{b}$. We needed to find the ratio $B:G$.
Percentage A fraction out of 100. $x\% = \frac{x}{100}$. Converted 15% to $\frac{15}{100}$ or $\frac{3}{20}$.
Fraction Represents a part of a whole or a division. Used $\frac{1}{3}$ for one-third of girls.
Algebraic Equation A statement that two mathematical expressions are equal. Set up the equation $\frac{3}{20} B = \frac{1}{3} G$.
Solving Equations Using inverse operations to find the value of a variable or expression. Rearranged the equation to solve for $\frac{B}{G}$.

Additional Information on Percentages, Fractions, and Ratios

Understanding how percentages, fractions, and ratios relate to each other is crucial for solving many math problems.

  • Percentages and Fractions: A percentage can always be written as a fraction with a denominator of 100. For example, 25% is $\frac{25}{100}$, which simplifies to $\frac{1}{4}$. Similarly, a fraction can be converted to a percentage by multiplying by 100%. For example, $\frac{1}{2} = \frac{1}{2} \times 100\% = 50\%$.
  • Fractions and Ratios: A fraction like $\frac{a}{b}$ directly represents the ratio $a:b$. This is why when we found $\frac{B}{G} = \frac{20}{9}$, we could immediately state the ratio $B:G$ is $20:9$. The numerator corresponds to the first part of the ratio, and the denominator corresponds to the second part.
  • Ratios and Proportions: A proportion is an equation stating that two ratios are equal, like $\frac{a}{b} = \frac{c}{d}$. The problem we solved is essentially setting up a proportion based on the given information and solving for an unknown ratio.

Being comfortable converting between these forms helps in setting up and solving such problems efficiently.

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Important Questions from Ratio and Proportion

  1. The cost of a diamond is directly proportional to the square of its weight. The cost of a 14 gm diamond is Rs. 2560. This diamond got broken down into two pieces in the ratio of 5 ∶ 9. How much loss percent is incurred due to this breakage ? (Correct to two decimal places)

  2. Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?

  3. A person divides a certain amount among his three sons in the ratio of 3 ∶ 4 ∶ 5. If he had divided this amount in the ratio of 1/3,1/4,1/5, his son, who had got the lowest share earlier, would get Rs.1,188 more. Find the amount (in Rs).

  4. In a school 3/8 of the number of students are girls and the rest are boys. One-third of the number of boys are below 10 years and 2/3 the number if girls are also below 10 years. If the number of students of age 10 or more years is 260. then the number of boys in the school is:

  5. If a : b : c = \(\frac{1}{4} : \frac{1}{3} : \frac{1}{2}, \)  then  \( \ \frac{a}{b} : \frac{b}{c} : \frac{c}{a} = ?\)

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