In a circuit, two resistors R₁ and R₂ are connected in parallel. If R₁ = 4 Ω and R₂ = 12 Ω, and the total voltage across the parallel combination is 6V, what is the total current flowing in the circuit?
2 A
For resistors in parallel, 1/R = 1/R1 + 1/R2.
1/R = 1/4 + 1/12 = 3/12 + 1/12 = 4/12, so R = 3 Ω.
By Ohm's law the total current is I = V/R = 6/3 = 2 A.
Hence, the answer is 2 A.
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