Decoding the Code Language Pattern

This question involves a coding pattern where letters in a word are replaced based on a specific rule. We need to figure out this rule using the given examples: 'CURVED' becomes 'FWSUCA', and 'LONDON' becomes 'OQOCMK'. Once we understand the pattern, we can apply it to find the code for 'SIMPLE'.

Analyzing the 'CURVED' to 'FWSUCA' Code

Let's look at the letter shifts from 'CURVED' to 'FWSUCA'. We can track the changes by looking at the position of each letter in the alphabet (A=1, B=2, etc.):

• C (3rd letter) to F (6th letter): The shift is \( 6 - 3 = +3 \).
• U (21st letter) to W (23rd letter): The shift is \( 23 - 21 = +2 \).
• R (18th letter) to S (19th letter): The shift is \( 19 - 18 = +1 \).
• V (22nd letter) to U (21st letter): The shift is \( 21 - 22 = -1 \).
• E (5th letter) to C (3rd letter): The shift is \( 3 - 5 = -2 \).
• D (4th letter) to A (1st letter): The shift is \( 1 - 4 = -3 \).

The pattern identified is: +3, +2, +1, -1, -2, -3. It applies sequentially to the letters of the word.

Verifying the Pattern with 'LONDON' to 'OQOCMK'

To ensure this pattern is correct, let's check it against the second example, 'LONDON' coded as 'OQOCMK':

• L (12) shifts by +3: \( 12 + 3 = 15 \). The 15th letter is O.
• O (15) shifts by +2: \( 15 + 2 = 17 \). The 17th letter is Q.
• N (14) shifts by +1: \( 14 + 1 = 15 \). The 15th letter is O.
• D (4) shifts by -1: \( 4 - 1 = 3 \). The 3rd letter is C.
• O (15) shifts by -2: \( 15 - 2 = 13 \). The 13th letter is M.
• N (14) shifts by -3: \( 14 - 3 = 11 \). The 11th letter is K.

The results match 'OQOCMK', confirming the coding pattern: +3, +2, +1, -1, -2, -3.

Applying the Code to 'SIMPLE'

Now, we apply this exact pattern to the word 'SIMPLE':

• S (19th letter): Apply +3. \( 19 + 3 = 22 \). The 22nd letter is V.
• I (9th letter): Apply +2. \( 9 + 2 = 11 \). The 11th letter is K.
• M (13th letter): Apply +1. \( 13 + 1 = 14 \). The 14th letter is N.
• P (16th letter): Apply -1. \( 16 - 1 = 15 \). The 15th letter is O.
• L (12th letter): Apply -2. \( 12 - 2 = 10 \). The 10th letter is J.
• E (5th letter): Apply -3. \( 5 - 3 = 2 \). The 2nd letter is B.

By applying the sequence of shifts, we get the coded letters: V, K, N, O, J, B.

Final Coded Word Result

Putting these letters together, the word 'SIMPLE' is coded as 'VKNOJB' using the established logic.