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Question

In a 500 m race, P and Q have speeds in the ratio of 3 ∶ 4. Q starts the race when P has already covered 140 m.

What is the distance between P and Q (in m) when P wins the race?

The correct answer is

20

Race Problem Analysis: P and Q's Performance

This problem involves understanding relative speeds and distances in a race scenario. We are given the total race distance, the speed ratio of two runners, P and Q, and a head start condition. The goal is to find the distance between P and Q when P wins the race.

Understanding the Race Setup

  • The total length of the race is 500 m.
  • The speeds of P and Q are in the ratio of 3 ∶ 4. This means if P's speed is \(3v\), then Q's speed is \(4v\) for some unit speed \(v\).
  • Q starts the race when P has already covered 140 m. This is a head start for P.
  • When P wins the race, P will have covered the full 500 m distance.

Calculating P's Winning Time

When Q starts, P has already covered 140 m. This means P is 140 m ahead of the starting line, and Q is at the starting line (0 m). For P to win the race, P must cover the remaining distance to reach the 500 m mark.

  • P's initial distance covered = 140 m.
  • Total race distance = 500 m.
  • Distance P needs to cover from the point Q starts = \(500 \text{ m} - 140 \text{ m} = 360 \text{ m}\).

Let's assume P's speed is \(3x\) units/time and Q's speed is \(4x\) units/time. To find the time taken for P to win the race from the 140 m mark, we use the formula: \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \).

Time taken by P to cover 360 m:

$$ \text{Time}_{\text{P wins}} = \frac{360 \text{ m}}{3x \text{ m/unit time}} = \frac{120}{x} \text{ unit time} $$

Determining Q's Progress

Q starts running at the same moment P is at the 140 m mark. Both P and Q run for the same duration until P crosses the finish line. We need to calculate how much distance Q covers in the time P takes to win the race.

  • Q's speed = \(4x\) units/time.
  • Time Q runs = \( \frac{120}{x} \) unit time (same as P's winning time).

Distance covered by Q in this time:

$$ \text{Distance}_{\text{Q covers}} = \text{Speed}_{\text{Q}} \times \text{Time}_{\text{P wins}} $$

$$ \text{Distance}_{\text{Q covers}} = 4x \text{ m/unit time} \times \frac{120}{x} \text{ unit time} $$

$$ \text{Distance}_{\text{Q covers}} = 4 \times 120 = 480 \text{ m} $$

When P wins the race (P is at 500 m), Q has covered 480 m from the starting line.

Final Distance Calculation

Now we need to find the distance between P and Q at the exact moment P wins the race.

  • P's position when P wins = 500 m (the finish line).
  • Q's position when P wins = 480 m (distance covered by Q from the start).

The distance between P and Q is the difference between their positions:

$$ \text{Distance between P and Q} = \text{P's position} - \text{Q's position} $$

$$ \text{Distance between P and Q} = 500 \text{ m} - 480 \text{ m} = 20 \text{ m} $$

Aspect P Q
Starting Position (when Q starts) 140 m 0 m
Speed Ratio 3 (e.g., \(3x\)) 4 (e.g., \(4x\))
Distance to Finish (from Q's start) 360 m 500 m
Time P takes to win (from 140m mark) \( \frac{360}{3x} = \frac{120}{x} \) unit time
Distance covered in this time 360 m (reaches 500m) \(4x \times \frac{120}{x} = 480\) m
Final Position when P wins 500 m 480 m
Distance between P and Q \(500 \text{ m} - 480 \text{ m} = 20 \text{ m}\)

Therefore, the distance between P and Q when P wins the race is 20 m.

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Important Questions from Ratio and Proportion

  1. In a mixture of 156 litres, the ratio of milk and water is 7 : 6. How much water should be added to make the ratio 14 : 13?

  2. If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:

  3. The third proportional to 9 and 15 is:

  4. The average age of 3 persons is 30 years.If their ages are in the ratio of 3 : 5 : 7 respectively, then the age of the eldest person is:

  5. The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio of 8 : 5 : 2. If C spends 2000 and B saves ₹ 700, then A saves:

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