In a 500 m race, P and Q have speeds in the ratio of 3 ∶ 4. Q starts the race when P has already covered 140 m. What is the distance between P and Q (in m) when P wins the race?
20
This problem involves understanding relative speeds and distances in a race scenario. We are given the total race distance, the speed ratio of two runners, P and Q, and a head start condition. The goal is to find the distance between P and Q when P wins the race.
When Q starts, P has already covered 140 m. This means P is 140 m ahead of the starting line, and Q is at the starting line (0 m). For P to win the race, P must cover the remaining distance to reach the 500 m mark.
Let's assume P's speed is \(3x\) units/time and Q's speed is \(4x\) units/time. To find the time taken for P to win the race from the 140 m mark, we use the formula: \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \).
Time taken by P to cover 360 m:
$$ \text{Time}_{\text{P wins}} = \frac{360 \text{ m}}{3x \text{ m/unit time}} = \frac{120}{x} \text{ unit time} $$
Q starts running at the same moment P is at the 140 m mark. Both P and Q run for the same duration until P crosses the finish line. We need to calculate how much distance Q covers in the time P takes to win the race.
Distance covered by Q in this time:
$$ \text{Distance}_{\text{Q covers}} = \text{Speed}_{\text{Q}} \times \text{Time}_{\text{P wins}} $$
$$ \text{Distance}_{\text{Q covers}} = 4x \text{ m/unit time} \times \frac{120}{x} \text{ unit time} $$
$$ \text{Distance}_{\text{Q covers}} = 4 \times 120 = 480 \text{ m} $$
When P wins the race (P is at 500 m), Q has covered 480 m from the starting line.
Now we need to find the distance between P and Q at the exact moment P wins the race.
The distance between P and Q is the difference between their positions:
$$ \text{Distance between P and Q} = \text{P's position} - \text{Q's position} $$
$$ \text{Distance between P and Q} = 500 \text{ m} - 480 \text{ m} = 20 \text{ m} $$
| Aspect | P | Q |
|---|---|---|
| Starting Position (when Q starts) | 140 m | 0 m |
| Speed Ratio | 3 (e.g., \(3x\)) | 4 (e.g., \(4x\)) |
| Distance to Finish (from Q's start) | 360 m | 500 m |
| Time P takes to win (from 140m mark) | \( \frac{360}{3x} = \frac{120}{x} \) unit time | |
| Distance covered in this time | 360 m (reaches 500m) | \(4x \times \frac{120}{x} = 480\) m |
| Final Position when P wins | 500 m | 480 m |
| Distance between P and Q | \(500 \text{ m} - 480 \text{ m} = 20 \text{ m}\) | |
Therefore, the distance between P and Q when P wins the race is 20 m.
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