If Z = 1 + i, where i = √-1, then what is the modulus of \(\rm z+\frac{2}{z}?\)
2
Let's find the modulus of the complex expression \( \rm z+\frac{2}{z} \) when \( z = 1 + i \).
First, we need to calculate the value of the expression \( \rm z+\frac{2}{z} \).
We are given \( z = 1 + i \).
Now, let's find \( \frac{2}{z} \):
\[ \frac{2}{z} = \frac{2}{1 + i} \]
To simplify this fraction, we multiply the numerator and the denominator by the conjugate of the denominator. The conjugate of \( 1 + i \) is \( 1 - i \).
\[ \frac{2}{1 + i} = \frac{2}{1 + i} \times \frac{1 - i}{1 - i} \]
Using the difference of squares formula \( (a+b)(a-b) = a^2 - b^2 \) in the denominator:
\[ (1 + i)(1 - i) = 1^2 - i^2 = 1 - (-1) = 1 + 1 = 2 \]
So, the expression becomes:
\[ \frac{2(1 - i)}{2} = 1 - i \]
Now, we add \( z \) and \( \frac{2}{z} \):
\[ z + \frac{2}{z} = (1 + i) + (1 - i) \]
Combine the real parts and the imaginary parts:
\[ z + \frac{2}{z} = (1 + 1) + (i - i) = 2 + 0i = 2 \]
The complex expression \( \rm z+\frac{2}{z} \) simplifies to the real number 2.
We found that \( z + \frac{2}{z} = 2 \). Now we need to find the modulus of this result.
For a complex number \( a + bi \), its modulus is given by \( |a + bi| = \sqrt{a^2 + b^2} \).
In our case, the complex number is 2, which can be written as \( 2 + 0i \). Here, \( a = 2 \) and \( b = 0 \).
The modulus is:
\[ \left| z + \frac{2}{z} \right| = |2 + 0i| = \sqrt{2^2 + 0^2} \]
\[ = \sqrt{4 + 0} = \sqrt{4} = 2 \]
Therefore, the modulus of \( \rm z+\frac{2}{z} \) is 2.
| Step | Calculation | Result |
|---|---|---|
| Given z | \(z = 1+i\) | |
| Calculate 2/z | \( \frac{2}{1+i} = \frac{2(1-i)}{(1+i)(1-i)} = \frac{2(1-i)}{2} \) | \( \frac{2}{z} = 1-i \) |
| Calculate z + 2/z | \( (1+i) + (1-i) = (1+1) + (i-i) \) | \( z + \frac{2}{z} = 2 \) |
| Calculate Modulus | \( |2| = \sqrt{2^2 + 0^2} = \sqrt{4} \) | \( \left| z + \frac{2}{z} \right| = 2 \) |
The modulus of a complex number \( z = a + bi \) represents its distance from the origin \((0, 0)\) in the complex plane. It is a non-negative real number.
In this problem, \( \rm z+\frac{2}{z} \) resulted in a purely real number, 2. The modulus of 2 is simply \( |2| \), which is 2.
| Concept | Description | Formula/Example |
|---|---|---|
| Complex Number | A number of the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i = \sqrt{-1}\). | \(z = 3 + 4i\) |
| Real Part | The number \(a\) in \(a + bi\). | For \(3 + 4i\), real part is 3. |
| Imaginary Part | The number \(b\) in \(a + bi\) (not including \(i\)). | For \(3 + 4i\), imaginary part is 4. |
| Conjugate | For \(a + bi\), the conjugate is \(a - bi\). | Conjugate of \(1+i\) is \(1-i\). |
| Modulus | The magnitude or length of the complex number from the origin in the complex plane. | \(|a+bi| = \sqrt{a^2 + b^2}\) |
Operating with complex numbers involves treating them somewhat like binomials, with the special rule that \(i^2 = -1\).
These operations are fundamental when working with complex numbers and their properties like modulus and argument.
What is the value of \({\left[ {\frac{{i + \sqrt 3 }}{2}} \right]^{2019}} + {\left[ {\frac{{i - \sqrt 3 }}{2}} \right]^{2019}}?\)
What is the modulus of z?
What is the principal argument of z?
What is the value of \({\left( {\frac{{ - 1 + i\sqrt 3 }}{2}} \right)^{3n}} + {\left( {\frac{{ - 1 - i\sqrt 3 }}{2}} \right)^{3n}}\) ?
Where \(i = \sqrt { - 1} ?\)
Which one of the following is correct in respect of the cube roots of unity?
The number of non-zero integral solutions of the equation |1 - 2i| x= 5 xis
If α and β are different complex numbers with |α | = 1, then what is \(\left| {\frac{{\alpha - \beta }}{{1 - \alpha \bar \beta }}} \right|\) equal to?
The modulus- amplitude form of \(\sqrt 3 + i\) , where \(i = \sqrt { - 1}\) is
What is the principal argument of (-1 –i), where i = \(\sqrt { - 1}\)
Let α and β be real numbers and z be a complex number. If z 2+ αz + β = 0 has two distinct non-real roots with Re(z) = 1, then it is necessary that.
If A + iB = tan (x + iy), then the value of tan 2x is?
If \(x + iy = \sqrt {\frac{{a + ib}}{{c + id}}}\), then the value of x2 + y2 is -
If x = cos θ + i sin θ, then the value of \({x^n} + \frac{1}{{{x^n}}}\) is:
If \(\left| {\begin{array}{*{20}{c}} {6i}&{ - 3i}&1\\ 4&{3i}&{ - 1}\\ {20}&3&i \end{array}} \right| = x + iy\), then the values of x and y are:
If iz3 + z2 - z + i = 0, then the value of |z| is: