This problem asks for the radius and surface area of a sphere where its volume is numerically equal to its surface area, using \(\pi = \frac{22}{7}\) and rounding to 3 decimal places.
The condition \(V = A\) translates to:
\( \frac{4}{3}\pi r^3 = 4\pi r^2 \)
To solve for the radius (\(r\)), we simplify the equation. Assuming \(r > 0\) (since it's a sphere):
Divide both sides by \(4\pi r^2\):
\( \frac{\frac{4}{3}\pi r^3}{4\pi r^2} = \frac{4\pi r^2}{4\pi r^2} \)
This simplifies to:
\( \frac{1}{3}r = 1 \)
Solving for \(r\) yields:
\( r = 3 \text{ units} \)
Using the calculated radius (\(r = 3\)) and the given \(\pi = \frac{22}{7}\), calculate the surface area (\(A\)):
\( A = 4\pi r^2 \)
\( A = 4 \times \frac{22}{7} \times (3)^2 \)
\( A = 4 \times \frac{22}{7} \times 9 \)
\( A = \frac{4 \times 22 \times 9}{7} \)
\( A = \frac{792}{7} \)
Converting to a decimal and rounding to three decimal places:
\( A \approx 113.143 \text{ unit}^2 \)
The radius of the sphere is 3 units, and its surface area is approximately 113.143 unit\(^2\).
The sides of the rectangle are in the ratio 8 : 10 and its perimeter is 90 cm. The area of this rectangle is:
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