If \(\triangle ABC \sim \triangle PQR\) and \(AB : PQ = 7 : 9\), then find the ratio of area of \(\triangle ABC\) to the area of \(\triangle PQR\).
49 : 81
When two triangles are similar, the ratio of their areas equals the square of the ratio of their corresponding sides.
Given AB : PQ = 7 : 9, the ratio of the areas of triangle ABC to triangle PQR = (7/9)² = 49/81.
Hence, the correct answer is 49:81.
Similar Questions
In △ABC, DE ∥ AC, where D and E are the points on sides AB and BC, respectively. If BD = 5 cm and AD = 14 cm, then what is the ratio of the area of △BDE to that of the trapezium ADEC?
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In \(\triangle XYZ\) and \(\triangle PQR\), if \(XY = PQ\) and \(YZ = QR\), then one can infer that \(\triangle XYZ \cong \triangle PQR\) when:
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Important Questions from Triangles, Congruence and Similarity
If sides of a triangle are 12 cm, 15 cm and 21 cm, then what is the inradius (in cm) of the triangle?
What is the area of quadrilateral ABCD?
It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?
Sides of two similar triangles are in the ratio 4 ∶ 9. Area of these triangles are in the ratio:
If the ratio of corresponding sides of 2 similar triangles is 2 ∶ 3. Then the ratio of their corresponding altitude is :
