The problem asks for the ratio of two sums, A and B, based on conditions involving simple interest.
The formula for Simple Interest (SI) is:
$SI = (Principal × Rate × Time) / 100$Where:
Principal = Rs. A
Rate = 6% per annum
Time = 2 years
Using the formula:
$SI_A = (A × 6 × 2) / 100$ $SI_A = (12A) / 100$Principal = Rs. B
Rate = 4% per annum
Time = 3 years
Using the formula:
$SI_B = (B × 4 × 3) / 100$ $SI_B = (12B) / 100$The problem states that the simple interest for A is equal to the simple interest for B:
$SI_A = SI_B$Substituting the calculated values:
$(12A) / 100 = (12B) / 100$To find the ratio A:B, we can solve the equation:
Multiply both sides by 100:
$12A = 12B$Divide both sides by 12:
$A = B$Now, rearrange to find the ratio A/B:
$A / B = 1 / 1$Therefore, the ratio of A to B (A:B) is 1:1.
A sum of ₹8000 is lent out in two parts, one at 5% simple interest and the other at 7% simple interest. If the annual interest is ₹500, the sum lent at 7% is:
What will the ratio be of the simple interest earned on a given amount at the same interest rate over 6 years compared to that earned over 9 years?
Pranav borrows a sum of ₹6,23,305 at the rate of 10% per annum simple interest. At the end of the first year, he repays ₹16,390 towards return of principal amount borrowed. If Pranav clears all pending dues at the end of the second year, including interest payment that accrued during the first year, how much does he pay (in ₹) at the end of the second year?
If ₹12,800 is invested in a bank for 5 years at the rate of 9% per annum simple interest. what amount is returned by the bank?
Somu has borrowed ₹10,000 from a money lender with simple interest at a rate of 7% half yearly. How much amount will he pay to the money lender after 3 years?
Find the Simple interest on Rs. 2,400 from 20 March 2019 to 31 may 2019 at \(6{1 \over 4}\) % rate?
If the simple interest for five years is equal is 35% of the principal, that rate of interest is:
A sum fetched a simple interest of Rs. 3,040 at the rate of 8% p.a in 5 years. what is the sum?