If the roots of the equation a (b - c) x 2+ b (c - a) x + c (a - b) = 0 are equal, then which one of the following is correct?
a, b and c are in HP
We are given a quadratic equation \(a(b - c) x^2 + b (c - a) x + c (a - b) = 0\). The question states that the roots of this equation are equal. We need to find the relationship between the coefficients \(a\), \(b\), and \(c\).
For a quadratic equation to have equal roots, its discriminant must be zero. However, let's first analyze the structure of this specific equation.
Let the given quadratic equation be in the standard form \(Ax^2 + Bx + C = 0\). By comparing the given equation with the standard form, we can identify the coefficients:
Let's calculate the sum of the coefficients \(A\), \(B\), and \(C\):
\(A + B + C = a(b - c) + b (c - a) + c (a - b)\)Expanding the terms, we get:
\(A + B + C = (ab - ac) + (bc - ab) + (ac - bc)\)Now, let's rearrange and cancel the terms:
\(A + B + C = ab - ab - ac + ac + bc - bc\) \(A + B + C = 0\)A key property of quadratic equations is that if the sum of its coefficients \(A + B + C\) is equal to zero, then \(x = 1\) is one of the roots of the equation \(Ax^2 + Bx + C = 0\).
The problem explicitly states that the roots of the equation are equal. We have just discovered that one root of the equation is \(x = 1\). Since the roots are equal, this means both roots must have the same value. Therefore, both roots of the given quadratic equation must be \(x = 1\).
For a quadratic equation \(Ax^2 + Bx + C = 0\) with roots \(\alpha\) and \(\beta\), the following relationships hold:
Since both roots are 1, we have \(\alpha = 1\) and \(\beta = 1\).
Let's use the property of the product of roots:
\(\alpha \beta = 1 \times 1 = 1\)So, we must have:
\(\frac{C}{A} = 1\) \(C = A\)Now, substitute the expressions for C and A in terms of \(a\), \(b\), and \(c\):
\(c(a - b) = a(b - c)\)Expand both sides:
\(ac - bc = ab - ac\)Rearrange the terms to find the relationship between \(a\), \(b\), and \(c\). Let's move the \(-ac\) from the right side to the left and \(-bc\) from the left side to the right:
\(ac + ac = ab + bc\) \(2ac = ab + bc\)This equation, \(2ac = ab + bc\), is the condition we were looking for. To understand what this means for the sequence \(a, b, c\), we can divide the entire equation by \(abc\) (assuming \(a, b, c\) are non-zero, which must be true if the equation is a valid quadratic with equal roots where \(a(b-c) \neq 0\)).
\(\frac{2ac}{abc} = \frac{ab}{abc} + \frac{bc}{abc}\)Simplifying each term:
\(\frac{2}{b} = \frac{1}{c} + \frac{1}{a}\)We can rewrite this as:
\(\frac{1}{a} + \frac{1}{c} = \frac{2}{b}\)This equation shows that \(\frac{1}{b}\) is the arithmetic mean of \(\frac{1}{a}\) and \(\frac{1}{c}\). This is the defining condition for three numbers \(a\), \(b\), and \(c\) to be in Harmonic Progression (HP). Three numbers are in HP if their reciprocals form an Arithmetic Progression (AP).
We could also use the sum of roots property \(\frac{-B}{A} = 2 \implies B = -2A\). Substituting the expressions: \(b(c-a) = -2a(b-c) \implies bc - ab = -2ab + 2ac \implies bc + ab - 2ac = 0\), which is the same condition \(2ac = ab + bc\).
Thus, if the roots of the equation \(a(b - c) x^2 + b (c - a) x + c (a - b) = 0\) are equal, the relationship \(\frac{1}{a} + \frac{1}{c} = \frac{2}{b}\) holds, which implies that \(a\), \(b\), and \(c\) are in Harmonic Progression (HP).
| Concept | Definition/Condition | Relevance to Problem |
|---|---|---|
| Equal Roots | Discriminant \(\Delta = B^2 - 4AC = 0\) | Given condition for the equation. |
| Sum of Coefficients = 0 | \(A+B+C=0\) | Implies \(x=1\) is a root for \(Ax^2+Bx+C=0\). |
| Roots are \(1, 1\) | Consequence of equal roots when sum of coefficients is 0. | Leads to \(C/A = 1\) and \(-B/A = 2\). |
| Condition \(2ac = ab+bc\) | Derived from \(C=A\). | Equivalent to \(a,b,c\) being in HP. |
| Harmonic Progression (HP) | Reciprocals \(\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\) are in AP (\(\frac{2}{b} = \frac{1}{a} + \frac{1}{c}\)). | The resulting relationship for \(a, b, c\). |
Arithmetic, Geometric, and Harmonic Progressions are types of sequences where terms follow specific rules.
Our analysis of the given quadratic equation with equal roots led directly to the condition \(\frac{2}{b} = \frac{1}{a} + \frac{1}{c}\), confirming that \(a, b, c\) are in Harmonic Progression.
If H is the Harmonic Mean of three numbers 10C4, 10C5, and 10C6, then what is the value of \(\frac{270}{H}\) ?
If the harmonic mean of 60 and x is 48, then what is the value of x?
If H is the harmonic mean of numbers 1, 2, 22, 23, ......2n-1 what is n/H equal to ?
If \(\dfrac{1}{b-a}+\dfrac{1}{b-c}=\dfrac{2}{b}\), then \(a, b\) and \(c\) are in
The nth terms of the two series 3 + 10 + 17 + ... and 63 + 65 + 67 + .... are equal, then the value of n is:
The value of n, for which \(\dfrac{a^{n+1} + b^{n+1}}{a^n+b^n}\) is the harmonic mean of a and b, is
Suppose that m and n are fixed numbers such that the mth term of an HP is equal to n and the nth term is equal to m, (m ≠ n). Then the (m + n)th term is:
If H is the Harmonic Mean of three numbers 10C4, 10C5, and 10C6, then what is the value of \(\frac{270}{H}\) ?
If the harmonic mean of 60 and x is 48, then what is the value of x?