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Question

If the random variable X has mean 3 and standard deviation 5, then what is the variance of the random variable Y = 2X - 5 ?

This question was previously asked in
NDA 1 2026 GAT Question Paper (12-Apr-2026)
The correct answer is
100

Variance Calculation for Transformed Random Variable

This question requires calculating the variance of a transformed random variable \(Y\) based on the properties of the original random variable \(X\). We are given the mean and standard deviation of \(X\).

Given Information:

  • Random variable \(X\) has mean \(\mu_X = 3\).
  • Random variable \(X\) has standard deviation \(\sigma_X = 5\).
  • The transformation is \(Y = 2X - 5\).

Key Variance Properties

Recall the properties of variance:

  • The variance is the square of the standard deviation: \(\text{Var}(X) = (\sigma_X)^2\).
  • For a linear transformation \(aX + b\), the variance is \(\text{Var}(aX + b) = a^2 \text{Var}(X)\). The constant term \(b\) does not affect the variance.

Step-by-Step Solution

  1. Calculate the variance of \(X\):

    Using the given standard deviation \(\sigma_X = 5\):

    \( \text{Var}(X) = (\sigma_X)^2 = 5^2 = 25 \)

  2. Calculate the variance of \(Y\):

    For the transformation \(Y = 2X - 5\), we have \(a=2\) and \(b=-5\). Apply the variance property:

    \( \text{Var}(Y) = \text{Var}(2X - 5) = 2^2 \times \text{Var}(X) \)

    Substitute the calculated \(\text{Var}(X)\):

    \( \text{Var}(Y) = 4 \times 25 = 100 \)

Final Answer

The variance of the random variable \(Y = 2X - 5\) is 100.

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