This question requires calculating the variance of a transformed random variable $Y$ based on the properties of the original random variable $X$. We are given the mean and standard deviation of $X$.
Recall the properties of variance:
Calculate the variance of $X$:
Using the given standard deviation $\sigma_X = 5$:
$ \text{Var}(X) = (\sigma_X)^2 = 5^2 = 25 $
Calculate the variance of $Y$:
For the transformation $Y = 2X - 5$, we have $a=2$ and $b=-5$. Apply the variance property:
$ \text{Var}(Y) = \text{Var}(2X - 5) = 2^2 \times \text{Var}(X) $
Substitute the calculated $\text{Var}(X)$:
$ \text{Var}(Y) = 4 \times 25 = 100 $
The variance of the random variable $Y = 2X - 5$ is 100.
The mean and variance of five observations are 14 and 13.2 respectively. Three of the five observations are 11, 16 and 20. What are the other two observations ?
A die is thrown 10 times and obtained the following outputs :
1, 2, 1, 1, 2, 1, 4, 6, 5, 4
What will be the mode of data so obtained ?
Consider the following frequency distribution :
| x | 1 | 2 | 3 | 5 |
| f | 4 | 6 | 9 | 7 |
What is the value of median of the distribution ?
For data -1, 1, 4, 3, 8, 12, 17, 19, 9, 11; if M is the median of first 5 observations and N is the median of last five observations, then what is the value of 4M - N ?
Let P, Q, R represent mean, median and mode. If for some distribution \(5 P=4 Q=\frac{R}{2}\) then what is \(\frac{P+Q}{2 P+0.7 R}\) equal to ?