If the number 4x315 is divisible by 3, where x is a digit, what can be the sum of all such values of x?
15
The question asks us to find the sum of all possible values of the digit 'x' in the number 4x315 such that the number is divisible by 3.
To solve this, we need to recall the divisibility rule for 3. A number is divisible by 3 if and only if the sum of its digits is divisible by 3.
Let's find the sum of the digits in the number 4x315. The digits are 4, x, 3, 1, and 5.
The sum of the digits is:
$$ \text{Sum of digits} = 4 + x + 3 + 1 + 5 $$
Adding the known digits:
$$ 4 + 3 + 1 + 5 = 13 $$
So, the sum of the digits is:
$$ \text{Sum of digits} = 13 + x $$
For the number 4x315 to be divisible by 3, the sum of its digits, which is $13 + x$, must be divisible by 3.
Since 'x' is a digit, its possible values are from 0 to 9 (i.e., 0, 1, 2, 3, 4, 5, 6, 7, 8, 9).
We need to find which of these values for 'x' make $13 + x$ divisible by 3. Let's test each possible value or think about multiples of 3 greater than or equal to 13.
The multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, ...
We are looking for values of $13 + x$ that are multiples of 3. Since 'x' is a digit (0-9), the minimum value of $13 + x$ is $13 + 0 = 13$, and the maximum value is $13 + 9 = 22$.
So, the possible multiples of 3 that $13 + x$ can be are 15, 18, and 21.
Therefore, the possible values for the digit 'x' are 2, 5, and 8.
The question asks for the sum of all such values of x. The possible values are 2, 5, and 8.
Sum of these values = $2 + 5 + 8$
$$ 2 + 5 + 8 = 15 $$
The sum of all possible values of x is 15.
| Value of x | Sum of digits (13 + x) | Is $13 + x$ divisible by 3? | Is x a valid digit (0-9)? | Is x a possible value? |
|---|---|---|---|---|
| 0 | 13 | No | Yes | No |
| 1 | 14 | No | Yes | No |
| 2 | 15 | Yes | Yes | Yes |
| 3 | 16 | No | Yes | No |
| 4 | 17 | No | Yes | No |
| 5 | 18 | Yes | Yes | Yes |
| 6 | 19 | No | Yes | No |
| 7 | 20 | No | Yes | No |
| 8 | 21 | Yes | Yes | Yes |
| 9 | 22 | No | Yes | No |
The possible values for x are indeed 2, 5, and 8. Their sum is 15.
| Rule | Explanation | Example |
|---|---|---|
| Sum of Digits | A number is divisible by 3 if the sum of its individual digits is a multiple of 3. | Is 123 divisible by 3? Sum of digits = 1 + 2 + 3 = 6. Since 6 is divisible by 3, 123 is divisible by 3. |
Understanding divisibility rules can help quickly determine if a number is divisible by another number without performing long division. Here are a few common rules:
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select the correct answer using the code given below: