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Question

If the number 4x315 is divisible by 3, where x is a digit, what can be the sum of all such values of x?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

15

Understanding Divisibility by 3

The question asks us to find the sum of all possible values of the digit 'x' in the number 4x315 such that the number is divisible by 3.

To solve this, we need to recall the divisibility rule for 3. A number is divisible by 3 if and only if the sum of its digits is divisible by 3.

Applying the Divisibility Rule to 4x315

Let's find the sum of the digits in the number 4x315. The digits are 4, x, 3, 1, and 5.

The sum of the digits is:

$$ \text{Sum of digits} = 4 + x + 3 + 1 + 5 $$

Adding the known digits:

$$ 4 + 3 + 1 + 5 = 13 $$

So, the sum of the digits is:

$$ \text{Sum of digits} = 13 + x $$

For the number 4x315 to be divisible by 3, the sum of its digits, which is $13 + x$, must be divisible by 3.

Finding Possible Values of the Digit 'x'

Since 'x' is a digit, its possible values are from 0 to 9 (i.e., 0, 1, 2, 3, 4, 5, 6, 7, 8, 9).

We need to find which of these values for 'x' make $13 + x$ divisible by 3. Let's test each possible value or think about multiples of 3 greater than or equal to 13.

The multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, ...

We are looking for values of $13 + x$ that are multiples of 3. Since 'x' is a digit (0-9), the minimum value of $13 + x$ is $13 + 0 = 13$, and the maximum value is $13 + 9 = 22$.

So, the possible multiples of 3 that $13 + x$ can be are 15, 18, and 21.

  • If $13 + x = 15$, then $x = 15 - 13 = 2$. Since 2 is a digit, x=2 is a possible value. ($13+2=15$, divisible by 3)
  • If $13 + x = 18$, then $x = 18 - 13 = 5$. Since 5 is a digit, x=5 is a possible value. ($13+5=18$, divisible by 3)
  • If $13 + x = 21$, then $x = 21 - 13 = 8$. Since 8 is a digit, x=8 is a possible value. ($13+8=21$, divisible by 3)
  • If $13 + x = 24$, then $x = 24 - 13 = 11$. Since 11 is not a single digit, this is not a possible value for x.

Therefore, the possible values for the digit 'x' are 2, 5, and 8.

Calculating the Sum of Possible Values of x

The question asks for the sum of all such values of x. The possible values are 2, 5, and 8.

Sum of these values = $2 + 5 + 8$

$$ 2 + 5 + 8 = 15 $$

The sum of all possible values of x is 15.

Summary of Possible x values
Value of x Sum of digits (13 + x) Is $13 + x$ divisible by 3? Is x a valid digit (0-9)? Is x a possible value?
0 13 No Yes No
1 14 No Yes No
2 15 Yes Yes Yes
3 16 No Yes No
4 17 No Yes No
5 18 Yes Yes Yes
6 19 No Yes No
7 20 No Yes No
8 21 Yes Yes Yes
9 22 No Yes No

The possible values for x are indeed 2, 5, and 8. Their sum is 15.

Revision Table: Key Concepts in Divisibility by 3

Divisibility Rule for 3
Rule Explanation Example
Sum of Digits A number is divisible by 3 if the sum of its individual digits is a multiple of 3. Is 123 divisible by 3? Sum of digits = 1 + 2 + 3 = 6. Since 6 is divisible by 3, 123 is divisible by 3.

Additional Information: Divisibility Rules

Understanding divisibility rules can help quickly determine if a number is divisible by another number without performing long division. Here are a few common rules:

  • Divisibility by 2: A number is divisible by 2 if its last digit is an even number (0, 2, 4, 6, 8).
  • Divisibility by 4: A number is divisible by 4 if the number formed by its last two digits is divisible by 4.
  • Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5.
  • Divisibility by 6: A number is divisible by 6 if it is divisible by both 2 and 3.
  • Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. (Similar to the rule for 3, but stricter).
  • Divisibility by 10: A number is divisible by 10 if its last digit is 0.

These rules are helpful for solving problems involving number properties and factors.

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