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Question

If the lines y + px = 1 and y - qx = 2 are perpendicular, then which one of the following is correct?

This question was previously asked in
NDA I 2021 GAT Previous Year Paper (18-Apr-2021)
The correct answer is

pq - 1 = 0

Understanding Perpendicular Lines and Their Slopes

When two lines in a coordinate plane are perpendicular, their slopes have a special relationship. The product of the slopes of two perpendicular lines is always -1, provided neither line is vertical or horizontal. Vertical lines have undefined slopes, and horizontal lines have a slope of 0. A vertical line is perpendicular to a horizontal line.

Let's consider the given equations of the lines:

  • Line 1: \(y + px = 1\)
  • Line 2: \(y - qx = 2\)

To find the slopes of these lines, we need to rewrite them in the slope-intercept form, which is \(y = mx + c\), where \(m\) is the slope and \(c\) is the y-intercept.

Converting Equations to Slope-Intercept Form

For the first line, \(y + px = 1\), we isolate \(y\) by subtracting \(px\) from both sides:

\(\qquad y = -px + 1\)

Comparing this to \(y = mx + c\), the slope of the first line, let's call it \(m_1\), is:

\(\qquad m_1 = -p\)

For the second line, \(y - qx = 2\), we isolate \(y\) by adding \(qx\) to both sides:

\(\qquad y = qx + 2\)

Comparing this to \(y = mx + c\), the slope of the second line, let's call it \(m_2\), is:

\(\qquad m_2 = q\)

Applying the Condition for Perpendicular Lines

The problem states that the two lines are perpendicular. The condition for two non-vertical perpendicular lines is that the product of their slopes is -1. That is, \(m_1 \times m_2 = -1\).

Substitute the slopes we found (\(m_1 = -p\) and \(m_2 = q\)) into this condition:

\(\qquad (-p) \times (q) = -1\)

\(\qquad -pq = -1\)

To find the relationship between \(p\) and \(q\), we can multiply both sides of the equation by -1:

\(\qquad pq = 1\)

Alternatively, we can move the constant term to the left side by subtracting 1 from both sides:

\(\qquad pq - 1 = 0\)

Comparing with the Given Options

Let's compare our derived relationship, \(pq - 1 = 0\), with the provided options:

  • Option 1: \(pq + 1 = 0\)
  • Option 2: \(p + q + 1 = 0\)
  • Option 3: \(pq - 1 = 0\)
  • Option 4: \(p - q + 1 = 0\)

Our derived condition \(pq - 1 = 0\) matches Option 3.

Summary of Steps

Step Description Calculation
1 Identify the equations of the lines. Line 1: \(y + px = 1\)
Line 2: \(y - qx = 2\)
2 Convert equations to slope-intercept form (\(y=mx+c\)). Line 1: \(y = -px + 1\)
Line 2: \(y = qx + 2\)
3 Identify the slopes (\(m_1\) and \(m_2\)). \(m_1 = -p\)
\(m_2 = q\)
4 Apply the perpendicularity condition (\(m_1 \times m_2 = -1\)). \((-p) \times (q) = -1\)
5 Simplify the equation. \(-pq = -1\)
\(pq = 1\)
\(pq - 1 = 0\)
6 Compare the result with the options. Matches \(pq - 1 = 0\)

Revision Table: Perpendicular Lines

Concept Description Condition
Perpendicular Lines Two lines that intersect at a right angle (90 degrees). Product of slopes is -1 (\(m_1 \times m_2 = -1\)), unless one line is vertical and the other is horizontal.
Slope of a Line A measure of the steepness of a line; represented as the change in y divided by the change in x (\(\frac{\Delta y}{\Delta x}\)). In \(y=mx+c\), the slope is \(m\).
Slope-Intercept Form A way to write the equation of a line: \(y = mx + c\), where \(m\) is the slope and \(c\) is the y-intercept. \(y = mx + c\)
Vertical Line A line parallel to the y-axis. Equation is \(x=a\); slope is undefined. Perpendicular to horizontal lines.
Horizontal Line A line parallel to the x-axis. Equation is \(y=b\); slope is 0. Perpendicular to vertical lines.

Additional Information on Line Relationships

Besides perpendicular lines, lines can also be parallel or intersecting non-perpendicularly.

  • Parallel Lines: Two lines are parallel if they have the same slope and different y-intercepts. The condition is \(m_1 = m_2\). If they have the same slope and the same y-intercept, they are the same line (coincident).
  • Intersecting Lines: Lines that cross each other at a single point. If their slopes are different (\(m_1 \neq m_2\)), they intersect. Perpendicular lines are a special case of intersecting lines.

Understanding the slopes of lines is fundamental in coordinate geometry for determining the relationship between lines.

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Important Questions from Lines

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