If the in-situ density of coal is 1320 kg/m$^3$ and the density of blasted coal is 952 kg/m$^3$, the swell factor is _____________ (rounded off to 3 decimal places)
This solution explains how to calculate the swell factor for coal using its in-situ and blasted densities. The swell factor indicates the change in volume or density after blasting.
Based on the typical context and the provided answer range (less than 1), the swell factor is calculated as the ratio of the density of blasted coal to the in-situ density of coal.
The formula is:
$ \text{Swell Factor} = \frac{\text{Density of blasted coal}}{\text{In-situ density of coal}} $
Substitute the values into the formula:
$ \text{Swell Factor} = \frac{952 \text{ kg/m}^3}{1320 \text{ kg/m}^3} $
$ \text{Swell Factor} \approx 0.721212... $
Rounding the value to 3 decimal places, as required:
$ \text{Swell Factor} = 0.721 $
The calculated swell factor is 0.721, which falls within the expected range of 0.7 to 0.74.
Three frictionless pulleys with rope attachment are in a static equilibrium as shown in the figure. The mass $m_1$ and $m_2$, in kg, respectively are

A five-member truss system is shown in the figure. The maximum vertical force P in kN that can be applied so that loads on the member CD and BC do NOT exceed 50 kN and 30 kN, respectively is _____________(rounded off to 2 decimal places)
The Fourier transform and its inverse transform are respectively defined as $\tilde{f}(\omega) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} f(x)e^{i\omega x}dx$ and $f(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} \tilde{f}(\omega)e^{-i\omega x}d\omega$. Consider two functions $f$ and $g$. Another function $f * g$ is defined as
$(f * g)(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} f(y)g(x - y)dy$
Which of the following relation is/are true?
Note: Tilde ($\sim$) denotes the Fourier transform.
The approximate value of the integral
$\int_{2}^{3} \frac{dx}{x}$
using Simpson's rule with $h = 0.5$ is