If the frequency of a sound wave of given velocity is increased, how will it affect its wavelength?
Its wavelength will decrease.
Let's explore the relationship between the properties of a sound wave: velocity, frequency, and wavelength. This relationship is fundamental to understanding wave behavior.
The velocity ($\mathbf{v}$) of a wave is the speed at which it travels through a medium. For sound, this speed depends on the properties of the medium, such as its temperature and density. The frequency ($\mathbf{f}$) of a wave is the number of wave cycles that pass a point per second, measured in Hertz (Hz). The wavelength ($\mathbf{\lambda}$) is the spatial period of the wave, or the distance over which the wave's shape repeats, measured in meters.
These three quantities are related by the following equation:
$\mathbf{v} = \mathbf{f\lambda}$
This equation tells us that the velocity of a wave is equal to the product of its frequency and its wavelength.
The question states that the velocity of the sound wave is given and constant. This means that if the frequency changes, the wavelength must also change in a way that keeps the product $f\lambda$ equal to the constant velocity $v$.
We can rearrange the formula to see how wavelength depends on frequency when velocity is constant:
$\mathbf{\lambda} = \frac{\mathbf{v}}{\mathbf{f}}$
From this rearranged formula, we can see that the wavelength ($\lambda$) is inversely proportional to the frequency ($f$) when the velocity ($v$) is held constant. This means if the frequency increases, the wavelength must decrease to keep the product constant. Conversely, if the frequency decreases, the wavelength must increase.
Let's look at the given options in light of this understanding:
When the speed of sound in a medium is constant, an increase in the frequency of the sound wave results in a corresponding decrease in its wavelength. This inverse relationship is a key concept in wave physics.
| Parameter | Change | Effect on Wavelength ($\lambda$) |
|---|---|---|
| Frequency ($\mathbf{f}$) | Increases | Decreases |
| Frequency ($\mathbf{f}$) | Decreases | Increases |
| Velocity ($\mathbf{v}$) | Constant | Determines the constant product of $f$ and $\lambda$ |
| Property | Symbol | Unit | Definition |
|---|---|---|---|
| Velocity | $\mathbf{v}$ | m/s | Speed of wave propagation |
| Frequency | $\mathbf{f}$ | Hz (1/s) | Number of cycles per second |
| Wavelength | $\mathbf{\lambda}$ | m | Length of one complete wave cycle |
While the question specifies a given, constant velocity, it's important to know that the speed of sound itself depends on the medium. For example:
So, if the medium or its conditions (like temperature for air) were to change, the velocity ($v$) would change, which would then affect the relationship between frequency and wavelength for a wave passing through it.
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