The relationship between the speed (\(v\)), frequency (\(f\)), and wavelength (\(\lambda\)) of a wave is fundamental in physics.
The formula connecting these properties is:
\( v = f \lambda \)
We are given the following conditions:
To determine the effect on the wavelength (\(\lambda\)), we can rearrange the wave equation:
\( \lambda = \frac{v}{f} \)
This equation shows that wavelength (\(\lambda\)) is inversely proportional to frequency (\(f\)) when the speed (\(v\)) is constant. An increase in frequency necessitates a decrease in wavelength to maintain a constant speed.
Therefore, if the frequency of a sound wave increases while its speed remains constant, its wavelength will decrease.
Which of the following is related to Doppler effect?
The position of a particle in one dimension changes in discrete steps. With each step it moves to the right, however, the length of the step is drawn from a uniform distribution from the interval \(\left[ {{\rm{λ }}\,{\rm{ - }}\,\frac{{\rm{1}}}{{\rm{2}}}{\rm{w,}}\,{\rm{λ }}\,{\rm{ + }}\,\frac{{\rm{1}}}{{\rm{2}}}{\rm{w}}} \right] \) , where λ and w are positive constants. If X denotes the distance from the starting point after N steps, the standard deviation \(\sqrt {\left\langle {{X^2}} \right\rangle \, - {{\left\langle X \right\rangle }^2}} \) for large values of N is
A particle of mass m in one dimension is in the ground state of a simple harmonic oscillator described by a Hamiltonian \(\frac{{{{\rm{P}}^{\rm{2}}}}}{{{\rm{2m}}}}{\rm{ + }}\frac{{\rm{1}}}{{\rm{2}}}{\rm{m}}{{\rm{\omega }}^{\rm{2}}}{{\rm{x}}^{\rm{2}}} \) in the standard notation. An impulsive force at time t = 0 suddenly imparts a momentum P0 = \(\sqrt {{\rm{hm\omega }}} \) to it. The probability that the particle remains in the original ground state is
In an elastic scattering process at an energy E, the phase shifts satisfy δ 0 ≈ 30°, δ 1≈ 10°, while the other phase shifts are zero. The polar angle at which the differential cross-section peaks is closest to