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Question

A broadcasting station transmits waves with a frequency of $71 \times 10^4\ Hz$ and a speed of $3 \times 10^8\ m/s$. The wavelength of the wave is:

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
422.5 m

Calculating Wave Wavelength

To find the wavelength of the waves transmitted by the broadcasting station, we use the fundamental wave equation that relates speed, frequency, and wavelength.

Wave Equation

The relationship between the speed of a wave ($v$), its frequency ($f$), and its wavelength ($\lambda$) is given by the formula:

$ v = f \lambda $

Solving for Wavelength

We need to rearrange the formula to solve for the wavelength ($\lambda$):

$ \lambda = \frac{v}{f} $

Given Values

  • Frequency ($f$): $71 \times 10^4\ Hz$
  • Speed ($v$): $3 \times 10^8\ m/s$

Calculation Steps

  1. Substitute the given values into the rearranged formula:

    $ \lambda = \frac{3 \times 10^8\ m/s}{71 \times 10^4\ Hz} $

  2. Simplify the expression:

    $ \lambda = \frac{3}{71} \times \frac{10^8}{10^4}\ m $

    $ \lambda = \frac{3}{71} \times 10^{(8-4)}\ m $

    $ \lambda = \frac{3}{71} \times 10^4\ m $

  3. Calculate the numerical value:

    $ \lambda \approx 0.0422535 \times 10^4\ m $

    $ \lambda \approx 422.535\ m $

  4. Round the result to match the options provided (one decimal place):

    $ \lambda \approx 422.5\ m $

Conclusion

The calculated wavelength of the wave is approximately $422.5\ m$. This corresponds to Option C.

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  2. If the frequency of a sound wave is 50 Hz, then what is its time period?

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