To find the wavelength of the waves transmitted by the broadcasting station, we use the fundamental wave equation that relates speed, frequency, and wavelength.
The relationship between the speed of a wave ($v$), its frequency ($f$), and its wavelength ($\lambda$) is given by the formula:
$ v = f \lambda $
We need to rearrange the formula to solve for the wavelength ($\lambda$):
$ \lambda = \frac{v}{f} $
$ \lambda = \frac{3 \times 10^8\ m/s}{71 \times 10^4\ Hz} $
$ \lambda = \frac{3}{71} \times \frac{10^8}{10^4}\ m $
$ \lambda = \frac{3}{71} \times 10^{(8-4)}\ m $
$ \lambda = \frac{3}{71} \times 10^4\ m $
$ \lambda \approx 0.0422535 \times 10^4\ m $
$ \lambda \approx 422.535\ m $
$ \lambda \approx 422.5\ m $
The calculated wavelength of the wave is approximately $422.5\ m$. This corresponds to Option C.
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A running race is organized between ultrasonics, audible and infrasonic waves in a medium, then the winner is:
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