If the area of a circle is 'a' square units, what will be the length of the side of an equilateral triangle inscribed in it?
sqrt(3a/pi)
Area = pi*r^2 = a, so r = sqrt(a/pi). The side of an equilateral triangle inscribed in a circle of radius r is r*sqrt(3) = sqrt(3a/pi).
In the given circle, O is the center, and A, B, C are points on the circle such that B lies on the arc joining A and C (the arc ABC). If the measure of arc ABC (from A to C passing through B) is 130°, what is the value of m∠ABC?
The sum of the radius and diameter of a circle is 84 cm. What is the circumference of this circle?
The maximum area of a right-angled triangle inscribed in a circle of radius r is
The tangent at a point C of a circle and diameter AB when extended intersect at D, if ∠DCA = 110°, then ∠CBA is equal to
The equation of a circle with diameters are 2x - 3y + 12 = 0 and x + 4y - 5 = 0 and area of 154 sq. units is
The internal center of similitude of two circles $ (x - 1)^2 + (y - 3)^2 = 4 $ and $ (x + 5)^2 + (y - 9)^2 = 16 $ is