We are given a scalar matrix M and need to find the value of the expression \(|M| |adjM|\).
The given matrix is:
\( M = \begin{bmatrix} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{bmatrix} \)
For a diagonal or scalar matrix, the determinant is the product of the diagonal elements.
For any \(n \times n\) matrix \(M\), the determinant of its adjoint matrix is related to the determinant of \(M\) by the formula:
\(|adjM| = |M|^{n-1}\)
In this case, \(M\) is a \(3 \times 3\) matrix, so \(n=3\).
Using the value of \(|M|\) calculated in Step 1:
Now, multiply the determinant \(|M|\) by the determinant of the adjoint \(|adjM|\):
Alternatively, we can directly calculate \(|M|^3\) since \(|M| |adjM| = |M| \cdot |M|^{n-1} = |M|^n\). For \(n=3\), this is \(|M|^3\).
The value of \(|M| |adjM|\) for the given matrix \(M\) is 512.
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?
If $A = \begin{bmatrix} \sin 2\theta & 2 \sin^2 \theta - 1 & 0 \\ \cos 2\theta & 2 \sin \theta \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$, then which of the following statements is/are correct?
1. $A^{-1} = \text{adj}A$
2. $A$ is skew-symmetric matrix
3. $A^{-1} = A^T$
Select the correct answer using the code given below :
If
\(\omega = -\frac{1}{2} + i\frac{\sqrt{3}}{2}\)
then what is
equal to?
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?