If f(x) = 4x + 1 and g(x) = kx + 2 such that fog(x) = gof(x), then what is the value of k ?
7
This problem asks us to find the value of a constant 'k' when the composition of two linear functions, f(x) and g(x), is commutative, meaning fog(x) = gof(x).
Function composition means applying one function to the result of another function. For two functions f(x) and g(x):
We are given the following linear functions:
And the condition: fog(x) = gof(x).
To find fog(x), we substitute g(x) into f(x):
\(\text{fog(x)} = \text{f(g(x))}\)
\(\text{fog(x)} = \text{f(kx + 2)}\)
Now, replace 'x' in f(x) with '(kx + 2)':
\(\text{fog(x)} = 4(\text{kx + 2}) + 1\)
\(\text{fog(x)} = 4\text{kx} + 8 + 1\)
\(\text{fog(x)} = 4\text{kx} + 9\)
To find gof(x), we substitute f(x) into g(x):
\(\text{gof(x)} = \text{g(f(x))}\)
\(\text{gof(x)} = \text{g(4x + 1)}\)
Now, replace 'x' in g(x) with '(4x + 1)':
\(\text{gof(x)} = \text{k(4x + 1)} + 2\)
\(\text{gof(x)} = 4\text{kx} + \text{k} + 2\)
We are given that fog(x) = gof(x). Let's set the expressions we found equal to each other:
\(4\text{kx} + 9 = 4\text{kx} + \text{k} + 2\)
Now, we need to solve this equation for the value of k. Notice that the term \(4\text{kx}\) appears on both sides of the equation. We can subtract \(4\text{kx}\) from both sides:
\(4\text{kx} + 9 - 4\text{kx} = 4\text{kx} + \text{k} + 2 - 4\text{kx}\)
This simplifies to:
\(9 = \text{k} + 2\)
To isolate k, subtract 2 from both sides of the equation:
\(9 - 2 = \text{k} + 2 - 2\)
This gives us:
\(7 = \text{k}\)
So, the value of k that satisfies the condition fog(x) = gof(x) is 7.
| Concept | Description | Example |
|---|---|---|
| Function Composition | Applying one function to the output of another. Notation: fog(x) or f(g(x)). | If f(x)=2x, g(x)=x+1, then fog(x)=f(x+1)=2(x+1)=2x+2. |
| Commutative Property | For function composition, this means fog(x) = gof(x). This property does not hold for all function pairs. | In this problem, f and g are commutative under composition for a specific k value. |
When composing two linear functions, say \(f(x) = ax + b\) and \(g(x) = cx + d\):
For fog(x) = gof(x), we need:
\(acx + ad + b = acx + cb + d\)
Subtracting \(acx\) from both sides gives:
\(ad + b = cb + d\)
This is the general condition for the composition of two linear functions \(ax+b\) and \(cx+d\) to be commutative. In our specific problem, \(a=4\), \(b=1\), \(c=k\), \(d=2\). Plugging these values into the general condition:
\(4(2) + 1 = k(1) + 2\)
\(8 + 1 = k + 2\)
\(9 = k + 2\)
\(k = 9 - 2\)
\(k = 7\)
This confirms the result obtained by directly calculating fog(x) and gof(x) for the given functions.
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