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Question

If f(x) = 4x + 1 and g(x) = kx + 2 such that fog(x) = gof(x), then what is the value of k ?

This question was previously asked in
NDA I 2022 GAT Previous Year Paper (10-Apr-2022)
The correct answer is

7

Finding the Value of k in Function Composition

This problem asks us to find the value of a constant 'k' when the composition of two linear functions, f(x) and g(x), is commutative, meaning fog(x) = gof(x).

Understanding Function Composition

Function composition means applying one function to the result of another function. For two functions f(x) and g(x):

  • fog(x) means f(g(x)) - we substitute the function g(x) into f(x).
  • gof(x) means g(f(x)) - we substitute the function f(x) into g(x).

Given Functions

We are given the following linear functions:

  • f(x) = 4x + 1
  • g(x) = kx + 2

And the condition: fog(x) = gof(x).

Calculating fog(x)

To find fog(x), we substitute g(x) into f(x):

\(\text{fog(x)} = \text{f(g(x))}\)

\(\text{fog(x)} = \text{f(kx + 2)}\)

Now, replace 'x' in f(x) with '(kx + 2)':

\(\text{fog(x)} = 4(\text{kx + 2}) + 1\)

\(\text{fog(x)} = 4\text{kx} + 8 + 1\)

\(\text{fog(x)} = 4\text{kx} + 9\)

Calculating gof(x)

To find gof(x), we substitute f(x) into g(x):

\(\text{gof(x)} = \text{g(f(x))}\)

\(\text{gof(x)} = \text{g(4x + 1)}\)

Now, replace 'x' in g(x) with '(4x + 1)':

\(\text{gof(x)} = \text{k(4x + 1)} + 2\)

\(\text{gof(x)} = 4\text{kx} + \text{k} + 2\)

Solving for k using the Condition fog(x) = gof(x)

We are given that fog(x) = gof(x). Let's set the expressions we found equal to each other:

\(4\text{kx} + 9 = 4\text{kx} + \text{k} + 2\)

Now, we need to solve this equation for the value of k. Notice that the term \(4\text{kx}\) appears on both sides of the equation. We can subtract \(4\text{kx}\) from both sides:

\(4\text{kx} + 9 - 4\text{kx} = 4\text{kx} + \text{k} + 2 - 4\text{kx}\)

This simplifies to:

\(9 = \text{k} + 2\)

To isolate k, subtract 2 from both sides of the equation:

\(9 - 2 = \text{k} + 2 - 2\)

This gives us:

\(7 = \text{k}\)

So, the value of k that satisfies the condition fog(x) = gof(x) is 7.

Summary of Steps to Find k

  1. Write down the given functions, f(x) and g(x).
  2. Calculate the composite function fog(x) = f(g(x)).
  3. Calculate the composite function gof(x) = g(f(x)).
  4. Set fog(x) equal to gof(x) based on the problem condition.
  5. Solve the resulting equation for the unknown constant k.

Revision Table: Function Composition

Concept Description Example
Function Composition Applying one function to the output of another. Notation: fog(x) or f(g(x)). If f(x)=2x, g(x)=x+1, then fog(x)=f(x+1)=2(x+1)=2x+2.
Commutative Property For function composition, this means fog(x) = gof(x). This property does not hold for all function pairs. In this problem, f and g are commutative under composition for a specific k value.

Additional Information: Linear Function Composition

When composing two linear functions, say \(f(x) = ax + b\) and \(g(x) = cx + d\):

  • fog(x) = f(cx + d) = a(cx + d) + b = acx + ad + b
  • gof(x) = g(ax + b) = c(ax + b) + d = acx + cb + d

For fog(x) = gof(x), we need:

\(acx + ad + b = acx + cb + d\)

Subtracting \(acx\) from both sides gives:

\(ad + b = cb + d\)

This is the general condition for the composition of two linear functions \(ax+b\) and \(cx+d\) to be commutative. In our specific problem, \(a=4\), \(b=1\), \(c=k\), \(d=2\). Plugging these values into the general condition:

\(4(2) + 1 = k(1) + 2\)

\(8 + 1 = k + 2\)

\(9 = k + 2\)

\(k = 9 - 2\)

\(k = 7\)

This confirms the result obtained by directly calculating fog(x) and gof(x) for the given functions.

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Similar Questions

  1. Consider the following statements:

    1. A function f : Z → Z, defined by f(x) = x + 1, is one-one as well as onto.

    2. A function f : N → N, defined by f(x) = x + 1, is one-one but not onto.

    Which of the above statements is/are correct?

  2. For \(x = \frac{{\sqrt \pi }}{2}\) , what is the value of [ho(gof)](x)?

  3. What is [fo(fof)](2) equal to?

  4. The function f(x) = |x| - x 3is

  5. Consider the following relations from \(A\) to \(B\), where \(A = \{1, 3, 5\}\) and \(B = \{2, 4, 6, 8\}\):

    I. \(\{(1,2), (3,2), (3,6), (5,8)\}\)

    II. \(\{(3,4), (5,8), (1,6), (3,2)\}\)

    III. \(\{(1,2), (3,6)\}\)

    IV. \(\{(1,6), (3,2), (5,2)\}\)

    Which of the above is/are function(s) from \(A\) to \(B\)?

  6. Consider the following statements in respect of the function \(f: R-\left\{\dfrac{3}{5}\right\} \to R-\left\{\dfrac{3}{5}\right\}\) such that \(f(x) = \dfrac{3x+2}{5x-3}\):

    I. \(f(x)\) is a bijective function.

    II. \(f^{-1}(x) = f(x)\)

    Which of the statements given above is/are correct?


Important Questions from Types of Functions

  1. The number of one-to-one functions from {1, 2, 3} to {1, 2, 3, 4, 5} is

  2. Consider the following statements:

    1. A function f : Z → Z, defined by f(x) = x + 1, is one-one as well as onto.

    2. A function f : N → N, defined by f(x) = x + 1, is one-one but not onto.

    Which of the above statements is/are correct?

  3. For \(x = \frac{{\sqrt \pi }}{2}\) , what is the value of [ho(gof)](x)?

  4. What is [fo(fof)](2) equal to?

  5. If A = {1, 2, 3} and B = {4, 5, 6}, then which of the following is bijective function?

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