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Question

For the following two (02) items:

 Let $p\sin^2 \alpha+q\cos^2 \alpha=m$, $q\sin^2 \beta+p\cos^2\beta=n$; $p \neq m, n$ and $q \neq m, n$.

If \(\alpha\) and \(\beta\) are complementary angles, then which one of the following is correct?

This question was previously asked in
CDS 2 2025 Maths Question Paper (14-Sep-2025)
The correct answer is
\(m-n=0\)

Trigonometric Equations Analysis

We are given two trigonometric equations:

  1. \(p\sin^2 \alpha+q\cos^2 \alpha=m\)
  2. \(q\sin^2 \beta+p\cos^2\beta=n\)

We are also told that the angles \(\alpha\) and \(\beta\) are complementary. This means their sum is \(90^\circ\) (or \(\frac{\pi}{2}\) radians).

Mathematically, \(\alpha + \beta = 90^\circ\).

Complementary Angle Condition

From the complementary angle relationship, we know:

  • \(\sin \beta = \sin(90^\circ - \alpha) = \cos \alpha\)
  • \(\cos \beta = \cos(90^\circ - \alpha) = \sin \alpha\)

Squaring both sides of these identities, we get:

  • \(\sin^2 \beta = \cos^2 \alpha\)
  • \(\cos^2 \beta = \sin^2 \alpha\)

Substituting into the Second Equation

Now, let's substitute these results into the second given equation (\(n\)):

Original Equation 2: \(q\sin^2 \beta+p\cos^2\beta=n\)

Substitute \(\sin^2 \beta = \cos^2 \alpha\) and \(\cos^2 \beta = \sin^2 \alpha\):

\(q(\cos^2 \alpha) + p(\sin^2 \alpha) = n\)

Rearranging the terms to match the format of Equation 1:

\(p\sin^2 \alpha + q\cos^2 \alpha = n\)

Comparing Equations for m and n

Now we have two expressions:

  • From Equation 1: \(p\sin^2 \alpha+q\cos^2 \alpha=m\)
  • From Equation 2 (after substitution): \(p\sin^2 \alpha+q\cos^2 \alpha=n\)

Since the left-hand sides of both expressions are identical (\(p\sin^2 \alpha+q\cos^2 \alpha\)), their right-hand sides must also be equal.

Therefore, we can conclude that \(m = n\).

Deriving the Final Relation

If \(m = n\), we can rearrange this equation to find the correct relationship among the options.

Subtracting \(n\) from both sides gives:

\(m - n = n - n\)

\(m - n = 0\)

This result matches the fourth option provided.

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