If a man lifts 1 kg of load to the height of 2.5 m from the ground‚ then assuming acceleration due to gravity is 10 m/sec2‚ magnitude of the work done by the man is _________.
25 joules
The correct answer is option 3 I.e. 25 Joules.
To calculate the work done by the man, you can use the formula:
W = m ×g × h
m is the mass (1 kg)
g is the acceleration due to gravity (10 m/s²)
h is the height (2.5 m)
The work done is:
W = 1 × 10 × 2.5 = 25 Joules
So, the magnitude of the work done by the man is 25 Joules.
If a force ‘F’ acts on a body such that body gets displaced through the distance ‘x’ in the direction of the force, then the work done by the force is ____________.
The kinetic energy of a moving object is dependent on which of the following quantities:
i) Mass of the body
ii) Square of the velocity
iii) Pressure
Which of the following statements refer/s to the law of conservation of energy?
Statements:
I) Energy can be converted from one form to another form of energy.
II) Energy can neither be created nor destroyed.
The work done in moving 10 coulomb charges across the potential difference of 5 volts is______.
The work done by a constant force of 5 Newton acting on a body is 5 joules. The Displacement of the body in the direction of the applied force is ______.
The kinetic energy of a body of mass 2 kg, which is moving with the constant velocity 5 m/sec, is .............
If a force ‘F’ acts on a body such that body gets displaced through the distance ‘x’ in the direction of the force, then the work done by the force is ____________.
The kinetic energy of a moving object is dependent on which of the following quantities:
i) Mass of the body
ii) Square of the velocity
iii) Pressure
Which of the following statements refer/s to the law of conservation of energy?
Statements:
I) Energy can be converted from one form to another form of energy.
II) Energy can neither be created nor destroyed.
The work done in moving 10 coulomb charges across the potential difference of 5 volts is______.