If A is a square matrix, then what is adj (A -1 ) – (adj A) -1 equal to?
Null matrix
The question asks us to determine the value of the expression \( \text{adj}(A^{-1}) - (\text{adj } A)^{-1} \) where \( A \) is a square matrix.
For the inverse of a matrix \( A \), denoted by \( A^{-1} \), and the adjoint of a matrix \( A \), denoted by \( \text{adj } A \), to exist, we must assume that \( A \) is an invertible square matrix. This means that the determinant of \( A \), denoted by \( |A| \), is non-zero \( (|A| \neq 0) \).
We will use the following fundamental properties of square matrices:
We know that \( \text{adj } A = |A| A^{-1} \) for an invertible matrix \( A \). Let's find the inverse of \( \text{adj } A \):
\[ (\text{adj } A)^{-1} = (|A| A^{-1})^{-1} \]
Using the property \( (cC)^{-1} = c^{-1} C^{-1} \) where \( c \) is a scalar and \( C \) is a matrix:
\[ (\text{adj } A)^{-1} = (|A|)^{-1} (A^{-1})^{-1} \]
Using the property \( (A^{-1})^{-1} = A \):
\[ (\text{adj } A)^{-1} = |A|^{-1} A \quad \text{ (Equation 1)} \]
Let \( B = A^{-1} \). Since \( A \) is invertible, \( A^{-1} \) is also invertible. We can use the property \( \text{adj } B = |B| B^{-1} \) for the matrix \( B \):
\[ \text{adj}(A^{-1}) = |A^{-1}| (A^{-1})^{-1} \]
Using the properties \( |A^{-1}| = |A|^{-1} \) and \( (A^{-1})^{-1} = A \):
\[ \text{adj}(A^{-1}) = |A|^{-1} A \quad \text{ (Equation 2)} \]
Now we substitute the results from Equation 1 and Equation 2 into the given expression:
\[ \text{adj}(A^{-1}) - (\text{adj } A)^{-1} = (|A|^{-1} A) - (|A|^{-1} A) \]
Since both terms are identical, their difference is the null matrix (a matrix of the same order as \( A \) with all its elements being zero).
\[ \text{adj}(A^{-1}) - (\text{adj } A)^{-1} = \mathbf{0} \]
Where \( \mathbf{0} \) represents the null matrix.
Let's look at the given options:
Our derived result is the null matrix.
| Expression Part | Derived Value |
|---|---|
| \( \text{adj}(A^{-1}) \) | \( |A|^{-1} A \) |
| \( (\text{adj } A)^{-1} \) | \( |A|^{-1} A \) |
| Difference | \( |A|^{-1} A - |A|^{-1} A = \mathbf{0} \) (Null Matrix) |
Therefore, \( \text{adj}(A^{-1}) – (\text{adj } A)^{-1} \) is equal to the Null matrix.
| Property | Description | Condition |
|---|---|---|
| \( A (\text{adj } A) = |A| I \) | Product of matrix and its adjoint | For any square matrix \( A \) |
| \( \text{adj } A = |A| A^{-1} \) | Adjoint in terms of inverse | For invertible matrix \( A \) \( (|A| \neq 0) \) |
| \( |A^{-1}| = |A|^{-1} \) | Determinant of inverse | For invertible matrix \( A \) \( (|A| \neq 0) \) |
| \( (A^{-1})^{-1} = A \) | Inverse of inverse | For invertible matrix \( A \) \( (|A| \neq 0) \) |
| \( (\text{adj } A)^{-1} = |A|^{-1} A \) | Inverse of adjoint | For invertible matrix \( A \) \( (|A| \neq 0) \) |
| \( \text{adj}(A^{-1}) = |A|^{-1} A \) | Adjoint of inverse | For invertible matrix \( A \) \( (|A| \neq 0) \) |
The Null Matrix (or Zero Matrix) is a matrix where all its elements are zero. It is usually denoted by \( \mathbf{0} \). For square matrices of the same order, adding or subtracting the null matrix does not change the matrix. For example, \( M + \mathbf{0} = M \) and \( M - \mathbf{0} = M \).
The Unit Matrix (or Identity Matrix) is a square matrix with ones on the main diagonal and zeros elsewhere. It is usually denoted by \( I \) or \( I_n \) (where \( n \) is the order of the matrix). It acts as the multiplicative identity for matrices, i.e., \( M I = I M = M \).
In this problem, the result of the expression \( \text{adj}(A^{-1}) - (\text{adj } A)^{-1} \) is the Null matrix, meaning it is a matrix filled entirely with zeros.
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