This problem requires calculating the number of elements in the union of two sets, denoted as $n(A \cup B)$. We are given the counts of elements in each set and their intersection.
The formula to find the number of elements in the union of two sets A and B is:
$n(A \cup B) = n(A) + n(B) - n(A \cap B)$Substitute the given values into the formula:
Therefore, the number of elements in the union of sets A and B is 51.
A student is free to choose only Chemistry, only Biology or both. If out of $32$ students, Chemistry has been chosen by $16$ and Biology by $25$, then how many students have chosen Biology but not Chemistry?