A student is free to choose only Chemistry, only Biology or both. If out of $32$ students, Chemistry has been chosen by $16$ and Biology by $25$, then how many students have chosen Biology but not Chemistry?
We are given the total number of students and the number of students who chose Chemistry and Biology. We need to find the number of students who selected Biology exclusively.
Use the Principle of Inclusion-Exclusion for two sets:
$|C \cup B| = |C| + |B| - |C \cap B|$
Substitute the given values into the formula to find the number of students who chose both subjects ($|C \cap B|$):
$32 = 16 + 25 - |C \cap B|$
$32 = 41 - |C \cap B|$
$|C \cap B| = 41 - 32$
$|C \cap B| = 9$
So, 9 students chose both Chemistry and Biology.
Calculate the number of students who chose only Biology. This is the total number of students who chose Biology minus those who chose both Biology and Chemistry:
$|B \setminus C| = |B| - |C \cap B|$
$|B \setminus C| = 25 - 9$
$|B \setminus C| = 16$
Therefore, 16 students have chosen Biology but not Chemistry.