This problem involves calculating the total number of students using provided percentages for sports participation and the count of non-participants.
The given data is:
We calculate the sum of percentages for distinct groups playing at least one game:
Total percentage of students playing at least one game = $30\% + 20\% + 10\% + 15\% + 10\% + 5\% + 5\% = 95\%$
The percentage of students playing no games is calculated as:
$100\% - (\text{Percentage playing at least one game}) = 100\% - 95\% = 5\%$
We are given that 15 students play no games. This 15 corresponds to the 5% calculated above.
Let '$T$' represent the total number of students.
The equation is:
$ 5\% \times T = 15 $
Converting percentage to a fraction:
$ \frac{5}{100} \times T = 15 $
Solving for '$T$':
$ T = 15 \times \frac{100}{5} $
$ T = 15 \times 20 $
$ T = 300 $
Thus, the total number of students is 300.
A student is free to choose only Chemistry, only Biology or both. If out of $32$ students, Chemistry has been chosen by $16$ and Biology by $25$, then how many students have chosen Biology but not Chemistry?