This problem involves finding the number of players in the intersection of two sets (Hockey and Cricket) within a larger group, given information about the total number of players and the sizes of various overlapping sets.
We use the Principle of Inclusion-Exclusion for three sets: H (Hockey), F (Football), and C (Cricket).
The formula is:
$|H \cup F \cup C| = |H| + |F| + |C| - |H \cap F| - |H \cap C| - |F \cap C| + |H \cap F \cap C|$Given values:
We need to find the number of players who play both Hockey and Cricket, denoted as $|H \cap C|$.
Substitute the known values into the Inclusion-Exclusion formula:
$44 = 26 + 24 + 24 - 8 - |H \cap C| - 12 + 5$Combine the known numbers:
$44 = (26 + 24 + 24 + 5) - (8 + 12) - |H \cap C|$ $44 = 79 - 20 - |H \cap C|$ $44 = 59 - |H \cap C|$Now, isolate $|H \cap C|$:
$|H \cap C| = 59 - 44$ $|H \cap C| = 15$Therefore, 15 players play both hockey and cricket.
A student is free to choose only Chemistry, only Biology or both. If out of $32$ students, Chemistry has been chosen by $16$ and Biology by $25$, then how many students have chosen Biology but not Chemistry?