The problem asks us to determine how many pens can be purchased for a specific amount (₹$200$) given the cost of a certain quantity of pens (8 pens for ₹$80$). This is a direct proportion problem.
First, find the cost of a single pen. We know that 8 pens cost ₹$80$.
Cost per pen = Total Cost / Number of Pens
Cost per pen = $\frac{₹80}{8 \text{ pens}}$
Cost per pen = $₹10$
So, each pen costs ₹$10$.
Now, use the cost per pen to find out how many pens can be bought for ₹$200$.
Number of Pens = Total Amount / Cost per Pen
Number of Pens = $\frac{₹200}{₹10 \text{ per pen}}$
Number of Pens = $20$ pens
Therefore, you can buy $20$ pens for ₹$200$.
If 3A = 4B = 5C, then A : B : C is equal to:
The monthly incomes of A and B are in the ration 3 : 5 and the ratio of their savings is 2 : 3 If the income of B is equal to three times the savings of A, then what is the ratio of the expenditures of A and B?
If an amount of Rs. 990 is divided among A, B and C in the ratio of 3 : 4 : 2, then B will get:
The ratio of boys and girls in a group is 7 : 6. If 4 more boys join the group and 3 girls leave the group, then the ratio of boys to girls becomes 4 : 3. What is the total number of boys and girls initially in the group?
The ratio of the number of boys to the number of girls in a school of 640 students, is 5 : 3. If 30 more girls are admitted in the school, then how many more boys should be admitted so that the ratio of boys to that of the girls, becomes 14 : 9.