The problem requires finding the value of the expression \(x-3\) after determining the value of \(x\) from the given linear equation \(4x+8=7\). The steps involve isolating \(x\) first, and then substituting its value into the expression \(x-3\).
Start with the given equation:
\(4x + 8 = 7\)
To isolate the term with \(x\), subtract 8 from both sides of the equation:
\(4x = 7 - 8\)
\(4x = -1\)
Now, divide both sides by 4 to find the value of \(x\):
\(x = \frac{-1}{4}\)
Substitute the value of \(x = -1/4\) into the expression \(x-3\):
\(x - 3 = \left(-\frac{1}{4}\right) - 3\)
To subtract 3 from \(-1/4\), find a common denominator, which is 4. Rewrite 3 as \(12/4\):
\(x - 3 = -\frac{1}{4} - \frac{12}{4}\)
Combine the fractions:
\(x - 3 = \frac{-1 - 12}{4}\)
\(x - 3 = \frac{-13}{4}\)
Thus, the value of \(x-3\) is \(-13/4\).
A man has equal number of five, ten and twenty rupee notes amounting to Rs. 385. Find the total number of notes?
The sum of three consecutive number is 126. Find the highest number?
Simplify 5x(x + 2) + 4x
A.5x 2+ 10
B.9x + 10
C.5x 2- 14x
D.5x 2+ 14xSolve:
x - 4 = -3
A. 7
B. -1
C. -7
D. 1
If 4(3x - 2) = 2(3x + 8), Then x = ?
A. 1
B. 2
C. 3
D. 4