The sum of three consecutive number is 126. Find the highest number?
43
Let's break down this problem step by step to find the highest of the three consecutive numbers that add up to 126.
Consecutive numbers are numbers that follow each other in order, with a difference of 1 between each number. For example, 5, 6, and 7 are consecutive numbers.
We need to represent the three consecutive numbers using algebra. Let the first number be represented by x.
The question states that the sum of these three consecutive numbers is 126. So, we can write an equation:
First number + Second number + Third number = 126
Substituting our algebraic expressions:
\(x + (x + 1) + (x + 2) = 126\)
Now, we need to solve this equation for x.
Combine the x terms and the constant terms:
\(x + x + 1 + x + 2 = 126\)
\(3x + 3 = 126\)
Subtract 3 from both sides of the equation to isolate the term with x:
\(3x + 3 - 3 = 126 - 3\)
\(3x = 123\)
Divide both sides by 3 to find the value of x:
\( \frac{3x}{3} = \frac{123}{3} \)
\(x = 41\)
So, the first number is 41.
Now that we know x = 41, we can find the other two consecutive numbers:
The three consecutive numbers are 41, 42, and 43.
The question asks for the highest number among these three consecutive numbers. Comparing 41, 42, and 43, the highest number is 43.
| Description | Number | Calculation |
|---|---|---|
| First Number | 41 | \(x\) |
| Second Number | 42 | \(x + 1\) |
| Third Number (Highest) | 43 | \(x + 2\) |
| Sum Check | 126 | \(41 + 42 + 43 = 126\) |
The sum of 41, 42, and 43 is indeed 126.
Therefore, the highest number is 43.
| Concept | Explanation |
|---|---|
| Consecutive Numbers | Numbers following each other in order, difference of 1. |
| Algebraic Representation | Using variables (like x, x+1, x+2) to represent unknown numbers. |
| Setting up Equation | Translating the word problem into a mathematical equation. |
| Solving Linear Equation | Using inverse operations to find the value of the variable. |
Consecutive integers can be positive, negative, or zero. The method used above works for any set of consecutive integers. If the problem involved an even sum or an odd sum, representing the numbers differently (e.g., x-1, x, x+1 or x, x+2, x+4 for consecutive even/odd) can sometimes simplify the algebra, but the x, x+1, x+2 method always works for any three consecutive integers.
For example, if the sum of three consecutive integers was 0, using x, x+1, x+2:
\(x + (x+1) + (x+2) = 0\)
\(3x + 3 = 0\)
\(3x = -3\)
\(x = -1\)
The numbers would be -1, 0, and 1, which are consecutive and sum to 0.
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