If 3 is added to each odd digit and 2 is subtracted from each even digit in the number 8254316, then how many digits will appear more than once in the new number thus formed?
Two
In 8254316, digits 8,2,4,6 are even (subtract 2 each) and 5,3,1 are odd (add 3 each).
Applying: \(8-2=6\), \(2-2=0\), \(5+3=8\), \(4-2=2\), \(3+3=6\), \(1+3=4\), \(6-2=4\).
New number: 6,0,8,2,6,4,4.
Digits appearing more than once: 6 (positions 1 and 5) and 4 (positions 6 and 7) — two digits.
Hence, two digits appear more than once in the new number.
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(NOTE: All operations to be done from left to right.)
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Important Questions from Number Based
Four number-pairs have been given, out of which three are alike in some manner and one is different. Select the number-pair that is different. (Any operation on digits is not allowed)
Four number-pairs have been given, out of which three are alike in some manner and one is different. Select the number-pair that is different.
Four number-pairs have been given, out of which three are alike in some manner and one is different. Select the number-pair that is different.
Four number-pairs have been given, out of which three are alike in some manner and one is different. Select the number-pair that is different.
Four number-pairs have been given, out of which three are alike in some manner and one is different. Select the number-pair that is different.
