The problem asks us to find the value of the variable y given a linear equation and the value of the variable x.
We are given the equation:
$2x + 3y = 23$
And we know that:
$x = 4$
To find y, we substitute the value of x (which is 4) into the given equation:
$2(4) + 3y = 23$
Now, we simplify and solve for y:
$8 + 3y = 23$
$3y = 23 - 8$
$3y = 15$
$y = \frac{15}{3}$
$y = 5$
Therefore, the value of y is 5.
If $2x - 3y = -1$ and $\frac{x}{x+y} = \frac{7}{12}$, then the value of $2xy$ is:
What is the solution of the following equations ?
2x + 3y = 12 and 3x − 2y = 5
Two positive numbers differ by 1280. When the greater number is divided by the smaller number, the quotient is 7 and the remainder is 50. The greater number is:
When 5 children from class A join class B, the number of children in both classes is the same. If 25 children from B, join A, then the number of children in A becomes double the number of children in B. The ratio of the number of children in A to those in B is:
If (x + 6y) = 8, and xy = 2, where x > 0, what is the value of (x 3+ 216y 3)?
If 8k 6+ 15k 3– 2 = 0, then the positive value of \(\left( {{\rm{k}}\,{\rm{ + }}\,\frac{1}{{\rm{k}}}} \right)\) is :